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Paladinen [302]
3 years ago
12

The equation of a line parallel to 2x−y+4=0 that passes through the point ( -1, 5) is ___?

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
5 0

Answer: y = 2x + 7

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

c represents y intercept

m represents the slope of the line.

The equation of the given line is

2x - y + 4 = 0

y = 2x + 4

Comparing with the slope intercept form, slope = 2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 1, 5) is 2

To determine the y intercept, we would substitute m = 2, x = - 1 and y = 5 into y = mx + c. It becomes

5 = 2 × - 1 + c

5 = - 2 + c

c = 5 + 2 = 7

The equation becomes

y = 2x + 7

IrinaK [193]3 years ago
3 0

Answer:

y=2x+7

Step-by-step explanation:

2x−y+4=0

y=2x+4

m=2

Line are parallel, so their slope is the same.

A(-1,5)... x1 =-1,y1 =5

y-y1 =m(x-x1)

y1 - 5=2(x-(-1))

y1 - 5=2(x+1)

y1-5=2x+2

y=2x+2+5

y=2x+7

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