3x + 5 = 23
5 more than(addition) 3 times(multiplication) a variable(x) is(equals) 23
(you add 5 to 3x)
If you need to solve for "x", you need to isolate/get the variable "x" by itself in the equation:
3x + 5 = 23 Subtract 5 on both sides
3x + 5 - 5 = 23 - 5
3x = 18 Divide 3 on both sides to get "x" by itself
x = 6
I believe you would do 2 times 3, which gives you 6. 3 is for the number of coin tosses, and 2 is the number of sides of a coin.
Answer:
C. [-5] < [-3] || D. [-4] < [-2]
Step-by-step explanation:
in A. 5 should be greater, > than -3
in B. 2 should be greater, > than -4
in C. its correct answer. true statement.
in D. its correct answer. true statement.
Answer:
The first one
Step-by-step explanation:
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