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UNO [17]
3 years ago
10

If the polygon is translated 4 units down and 5 units right, what will the coordinates of the new image be? Use prime notation i

n expressing the new coordinates.

Mathematics
1 answer:
Rama09 [41]3 years ago
6 0
Coordinate A: (-1, 1)
Coordinate B: (-1, -2) 
Coordinate C: (3, -2)
Coordinate D: (3, 2)

It's a simple matter of addition and subraction, or just common sense. Since you're going down four units, subtract the y-coordinate for each number by 4. Since you're moving to the right five units, add five to each x-coordinate. Then you're done! Hope this helps:)

~Ash
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Which statement about the angle measures is true?
sattari [20]

Answer:

Option (4)

Step-by-step explanation:

By the property of exterior angle of a triangle,

"Exterior angle of a triangle is equal to the sum of two opposite interior angles."

In the triangle ABC,

∠ACD is an exterior angle and ∠BAC and ∠ABC are the opposite interior angles.

m∠ACD = m∠BAC + m∠ABC

95° = m∠BAC + m∠ABC

Therefore, Option (4) will be the correct option.

5 0
4 years ago
The red line below is perpendicular to which of the following
yawa3891 [41]

Answer:

The y axis

Step-by-step explanation:

Perpendicular means for a line to create a 90 degree angle, like it does on the y axis.

Hope this helps!

8 0
3 years ago
If point P is 3/7 the distance from A to B, then it is ____ the distance from B to A.
IrinaVladis [17]

The answer is 4/7, because if A to P is 3/7 of the way, going to B would be to the end. So, you have to go 4/7 of the way to get to the end.

5 0
4 years ago
Read 2 more answers
Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Ymorist [56]

Answer:

a) 183-1.984\frac{20}{\sqrt{100}}=179.032    

183+1.984\frac{20}{\sqrt{100}}=186.968    

So on this case the 95% confidence interval would be given by (179.032;186.968)    

b) 190-1.984\frac{23}{\sqrt{100}}=185.437    

190+1.984\frac{23}{\sqrt{100}}=194.563    

So on this case the 95% confidence interval would be given by (185.437;194.563)    

c) For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Part a : Summer

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=100-1=99

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that t_{\alpha/2}=1.984

Now we have everything in order to replace into formula (1):

183-1.984\frac{20}{\sqrt{100}}=179.032    

183+1.984\frac{20}{\sqrt{100}}=186.968    

So on this case the 95% confidence interval would be given by (179.032;186.968)    

Part b: Winter

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=100-1=99

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that t_{\alpha/2}=1.984

Now we have everything in order to replace into formula (1):

190-1.984\frac{23}{\sqrt{100}}=185.437    

190+1.984\frac{23}{\sqrt{100}}=194.563    

So on this case the 95% confidence interval would be given by (185.437;194.563)    

Part c

For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

5 0
3 years ago
The area of a rectangular book cover is 4x2 - 6x-40. The width of the book
Vinil7 [7]

Step-by-step explanation:

4x^2-6x-40

2(2x^2-3x-20)

=2(2x+5)(x-4)

8 0
3 years ago
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