Complete Question:
Kyle held a balloon 8 feet off the ground, straight above his head. Ava is standing 15 feet directly to the right of Kyle.
Write an equation using the Pythagorean Theorem to find the value of x.
How far are Ava's feet from the balloon?
Answer:
Ava's feet is 17ft away from the balloon
Step-by-step explanation:
Given
![height = 8ft](https://tex.z-dn.net/?f=height%20%3D%208ft)
![distance = 15ft](https://tex.z-dn.net/?f=distance%20%3D%2015ft)
The attached image represents the scenario
Using Pythagoras theorem (from the attachment), we have:
![x^2 = 8^2 + 15^2](https://tex.z-dn.net/?f=x%5E2%20%3D%208%5E2%20%2B%2015%5E2)
![x^2 = 64 + 225](https://tex.z-dn.net/?f=x%5E2%20%3D%2064%20%2B%20225)
![x^2 =289](https://tex.z-dn.net/?f=x%5E2%20%3D289)
Take square roots of both sides
![x = \sqrt{289](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B289)
![x = 17](https://tex.z-dn.net/?f=x%20%3D%2017)
Answer: 72250 dollars
Step-by-step explanation:
Just divide 289000 by 4 and you get 72250 dollars
You multiply fractions simply by multiplying numerators and denominators with each other:
![-\dfrac{1}{4} \times \left(-\dfrac{6}{11}\right) = \dfrac{1 \times 6}{4 \times 11} = \dfrac{6}{44} = \dfrac{3}{22}](https://tex.z-dn.net/?f=%20-%5Cdfrac%7B1%7D%7B4%7D%20%5Ctimes%20%5Cleft%28-%5Cdfrac%7B6%7D%7B11%7D%5Cright%29%20%3D%20%5Cdfrac%7B1%20%5Ctimes%206%7D%7B4%20%5Ctimes%2011%7D%20%3D%20%5Cdfrac%7B6%7D%7B44%7D%20%3D%20%5Cdfrac%7B3%7D%7B22%7D%20)
<span>With algebraic expressions, you can’t add and subtract any terms like you can add and subtract numbers. Terms must be like terms in order to combine them. So, you can’t always simplify an algebraic expression by following the order of operations. You have to use the distributive property to rewrite the expression and then combine like terms to simplify. With numeric expressions, you can either simplify inside the parentheses first or use the distributive property first.</span>
Answer:
is the number of quarters and
is the number of dimes
Step-by-step explanation:
we know that
![1\ dime=\$0.10](https://tex.z-dn.net/?f=1%5C%20dime%3D%5C%240.10)
![1\ quarter=\$0.25](https://tex.z-dn.net/?f=1%5C%20quarter%3D%5C%240.25)
Let
x-----> the number of dimes
y------> the number of quarters
we know that
-----> equation A
----Isolate the variable y
-----> equation B
Substitute equation B in equation A
Find the value of y
![y=30-x](https://tex.z-dn.net/?f=y%3D30-x)
![y=30-14=16\ quarters](https://tex.z-dn.net/?f=y%3D30-14%3D16%5C%20quarters)
therefore
is the number of quarters and
is the number of dimes