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3 years ago

The ________ is the number of square units in the interior of a figure.

Mathematics

1 answer:

Over [174]3 years ago

5 0

The ________ is the number of square units in the interior of a figure

area would be the answer

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What is the simplified form of -9m^-2n^5 times 2m^-3n^-6

vazorg [7]

Answer:

-18m^6n^-30

Step-by-step explanation:

combining like terms

8 0

3 years ago

Which choices are equivalent to the expression below? Check all that apply. 6√3

Westkost [7]

Answer:

case A. $\sqrt{18}*\sqrt{6}$

case B. $\sqrt{108}$

case E. $\sqrt{3}*\sqrt{36}$

Step-by-step explanation:

we have

$6\sqrt{3}$

we know that

$6\sqrt{3}=\sqrt{36*3}=\sqrt{108}$

Verify each case

case A) $\sqrt{18}*\sqrt{6}$

$\sqrt{18}*\sqrt{6}=\sqrt{18*6}=\sqrt{108}$

therefore

$\sqrt{18}*\sqrt{6}$ is equivalent to $6\sqrt{3}$

case B) $\sqrt{108}$

$\sqrt{108}$ is equivalent to $6\sqrt{3}$

case C) $\sqrt{3}*\sqrt{6}$

$\sqrt{3}*\sqrt{6}=\sqrt{18}$

therefore

$\sqrt{18}$ is not equivalent to $6\sqrt{3}$

case D) $\sqrt{54}$

$\sqrt{54}$ is not equivalent to $6\sqrt{3}$

case E) $\sqrt{3}*\sqrt{36}$

$\sqrt{3}*\sqrt{36}=\sqrt{108}$

therefore

$\sqrt{3}*\sqrt{36}$ is equivalent to $6\sqrt{3}$

case F) $108$

$108$ is not equivalent to $6\sqrt{3}$

6 0

3 years ago

(5x)/7 - x/14 = 9/7 solve for the unknown value this is a linear equation

Ahat [919]

Step-by-step explanation:

$\longmapsto \rm \dfrac{5x}{7} - \dfrac{x}{14} = \dfrac{9}{7} \\$

$\longmapsto \rm \dfrac{10x + x}{14} = \dfrac{9}{7} \\$

$\longmapsto \rm \dfrac{11x}{14} = \dfrac{9}{7} \\$

→ 11x(7) = 14(9)

→ 77x = 126

→ x = 126 ÷ 77

→ x = 1.63

7 0

3 years ago

Angel saved $100 a week for a year. She spent 40%

Nastasia [14]

Answer:

40 because 40 percent of 100 is 40. You can just multiply the number by the percentage $100x40%

6 0

3 years ago

There are 4 different math courses, 5 different science courses, and 2 different history courses. If a student must take one of

rusak2 [61]

A student can take three subjects in 40 ways.

SOLUTION:

Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.

A student must take one of each, how many different ways can this be done?

Now, number ways to take math course = 4

Number of ways to take science course = 5

Number of ways to take history course = 2

So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.

Hence, a student can take three subjects in 40 ways.

6 0

3 years ago