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ivann1987 [24]
3 years ago
8

Apply the distributive property to factor out the greatest common factor 22c+33d

Mathematics
1 answer:
Tems11 [23]3 years ago
5 0
What you need to do is find a common multiple which is 11, Then you divide 22c and 33d by 11 so you get 2c and 3d Then since there is an addition sign you put 2c and 3d is () 
The Final answer is
11(2c+3d)
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baherus [9]

Answer:

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Step-by-step explanation:

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Thepotemich [5.8K]

Answer:

the average of this new list of numbers is 94

Step-by-step explanation:

Hello!

To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96

for the first list

\frac{a+b+c+80}{4} =90

for the new list

\frac{a+b+c+96}{4} =X

To solve this problem consider the following

1.X is the average value of the second list

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a + b + c = Y to create two new equations

for the first list

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for the second list

\frac{y+96}{4} =X\\

\frac{280+96}{4} =X\\x=94

the average of this new list of numbers is 94

4 0
3 years ago
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Express the following quantities as ordinary decimal numbers: (use solution)
MissTica

Step-by-step explanation:

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Answer:

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<u>Answer</u>:

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