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timama [110]
3 years ago
10

One number is 2 less than two-thirds the other. Their sum is 103. Find the two numbers

Mathematics
2 answers:
vazorg [7]3 years ago
8 0
X = 2/3y - 2
x + y = 103

2/3y - 2 + y = 103
2/3y + y = 103 + 2
5/3y = 105
y = 105 * 3/5
y = 315/5 = 63

x + y = 103
x + 63 = 103
x = 103 - 63
x = 40

so ur 2 numbers are : 63 and 40
skad [1K]3 years ago
3 0
X + (2x/3 - 2) = 103 : Write the expression.
x + 2x/3 - 2 = 103 : Remove parentheses.
(x + 2x/3 - 2) × 3 = 103 × 3 : Multiply both sides by 3 to remove the fraction.
3x + 2x - 6 = 309 : Evaluate.
5x - 6 = 309 : Combine like terms
5x - 6 + 6 = 309 + 6 : Isolate x by adding 6 to each side.
5x / 5 = 315 / 5 : Divide by x to find its value.
x = 63.
63 is one of the number. Now, find the second number using its quantity.
2x / 3 - 2
2(63) / 3 - 2
126 / 3 - 2 = 40.
One of the numbers is 63, and the other number is 40.
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What's the scientific notation of 0.000000109
Over [174]
0.000000109 in scientific notation will look as it follows:

1.09 * 10^-7

or
<span>
1.09 E-7

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5 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

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\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
2 years ago
I’m really struggling would really appreciate if someone could help!!!!!
ladessa [460]

9514 1404 393

Answer:

  A)  29/40

Step-by-step explanation:

The formula for this is ...

  P(A or B) = P(A) + P(B) - P(A and B)

Filling in the given values, you have ...

  P(A or B) = 9/20 +1/2 - 9/40

  P(A or B) = 18/40 +20/40 -9/40 = (18+20-9)/40

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Step-by-step explanation:

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Step-by-step explanation:

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