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3 years ago

Can someone help me please ? I'm trying to hurry and get this done

Mathematics

1 answer:

bonufazy [111]3 years ago

8 0

2.50 + 0.85p = 28.85 <== ur equation
0.85p = 28.85 - 2.50
0.85p = 26.35
p = 26.35/0.85
p = 31......so they gifts weighed 31 lbs

3 times the sum of a number and 5 times the number is 36...
3(n + 5n) = 36
3(6n) = 36
18n = 36
n = 36/18
n = 2........I am not 100% sure on this one

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Answer the 3 screenshotted questions below. 30 points!

Triss [41]

Answer:

13. $36a^2b^4$ π

14. $16x^3y^4$ π

15. $-\frac{c^3}{4a^7b^3}$

Step-by-step explanation:

13.

A = π * $r^2$

r = $6ab^2$

A = π* $(6ab^2)^2$

A = π * $(6ab^2)(6ab^2)$

A = π * $36a^2b^4$

A = $36a^2b^4$ π

14.

V = π * $r^2$ * h

r = $2x$

h = $4xy^4$

V = π * $(2x)^2$ * $4xy^4$

V = π * $4x^2$ * $4xy^4$

V = π * $16x^3y^4$

V = $16x^3y^4$ π

15. $\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$ = $-\frac{c^3}{4a^7b^3}$

$\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$

$\frac{a^{-4}}{-4a^3b^5c^{-3}}$

$\frac{b^2}{-4^{3+4}b^5c^{-3}}$

$\frac{b^2}{-4^7b^5c^{-3}}$

$\frac{1}{-4a^7b^{5-2}c^{-3}}$

$\frac{1}{-4a^7b^3c^{-3}}$

$\frac{c^3}{-4a^7b^3}$

$-\frac{c^3}{4a^7b^3}$

Hope this helps!

3 0

3 years ago

Starting from the same place, Miranda walks due west and Blake walks due east.

garri49 [273]

Going by 30 for east and -30 for west

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3 years ago

Which expression represents the height of the triangular base of the pyramid?

coldgirl [10]

The angle in the triangle = 60 degrees

so tan 60 = h / (1/2) s = 2h /s
sqrt3 = 2h / s

h = sqrt3 s / 2

B is the correct choice

8 0

3 years ago

Read 2 more answers

Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited thre

Lera25 [3.4K]

Answer:

$36 400

Step-by-step explanation:

Step 1

The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.

The amount deposited in January is $\$100.$