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V125BC [204]
3 years ago
6

Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited thre

e times the amount he deposited in the previous month. On June 15 of the same year, the total amount Mr. Jamison has deposited is $
Mathematics
2 answers:
tester [92]3 years ago
7 0

Answer:

36,400

Step-by-step explanation:

Lera25 [3.4K]3 years ago
5 0

Answer:

$36 400

Step-by-step explanation:

Step 1

The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.

The amount deposited in January is  \$100.

The amount deposited in February is 1\$00\times 3= \$300.

The amount deposited in March is  \$300\times 3= \$900.

The amount deposited in April is  \$900\times 3= \$2\700.

The amount deposited in May is  \$2\,700\times 3= \$8\,100.

The amount deposited in June is  \$8\,100\times 3= \$24\,300.


Step 2

The next step is to add up all the money that was deposited into the account. This calculation is shown below,

\$100+\$300+900+\$\$2\,700+\$8\,100+\$24\,000=\$36\,400


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Answer with Step-by-step explanation:

We are given that height of projectile after t seconds is given by

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t^2-6t+9=0

t^2-3t-3t+9=0

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t-3=0

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After 3 s, the height of the project will be 144 feet in the air.

b.h(t)=0

96t-16t^2=0

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At t=0, the initial position of projectile

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3 years ago
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Literal equations 5y-72=7+5x
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Evaluate arithmetic series:-<br><br> Step-by-step answer, please!
lorasvet [3.4K]

Let's see

\\ \rm\Rrightarrow {\displaystyle{\sum^{275}_{k=1}}}(-5k+12)

\\ \rm\Rrightarrow (-5(1)+12)+(-5(2)+12)\dots (-5(275)+12)

\\ \rm\Rrightarrow 7+5+3+2+1+\dots -1363

So

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Sum:-

\\ \rm\Rrightarrow S_n=\dfrac{n}{2}[a+l]

\\ \rm\Rrightarrow \dfrac{275}{2}(7-1363)

\\ \rm\Rrightarrow \dfrac{275}{2}(-1356)

\\ \rm\Rrightarrow 275(-678)

\\ \rm\Rrightarrow -186450

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2 years ago
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\bf \cfrac{s}{s}=\cfrac{\sqrt{64}}{\sqrt{81}}\implies \cfrac{s}{s}=\cfrac{8}{9}\qquad \leftarrow \textit{ratio of the sides or scale factor}

6 0
3 years ago
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