Let

denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by

, each independently and identically distributed with distribution

.
You want to find

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

Recall that if

, then the sampling distribution

with

being the size of the sample.
Transforming to the standard normal distribution, you have

so that in this case,

and the probability is equivalent to

Answer:
<em>x = 1</em>
<em>y = 1</em>
Step-by-step explanation:
<u>System of Equations</u>
We are given the system of equations:
2x + y = 3
x = 2y - 1
Substituting x in the first equation:
2(2y - 1) + y = 3
Operating:
4y - 2 + y = 3
5y = 3 + 2
y = 5/5 = 1
y = 1
Since:
x = 2y - 1
Then:
x = 2(1) - 1
x = 1
Solution:
x = 1
y = 1
1 is in the tens place
we look at 2
2 <5 so we leave it alone
6,310
Choice B
Answer:
10 pieces
Step-by-step explanation:
basically you divide 7.5 by .75 which equals 10.
You do that because you are seeing how many 3/4 inch pieces are in 7 and a half inches of ribbon and 7 1/2 = 7.5 and 3/4= .75