It is not possible for 120 kids and 20 adults to go on the trip, but 120 students can go with a maximum of 12 adults so the expense of the trip can fall in the school's budget.
We know that tickets of the zoo cost $15 for adults and $11 for children.
The equation representing the budget for the trip is 15x + 11y = 1500.
where, x is the no. of adults and y is the number of children that are travelling.
If x = 20 and y = 120 then,
15(20)+11(120)=300+1320=1620 which is out of the budget of the school.
If 120 students want to go to school then, no. of adults that can travel can be determined as
15 x + 11 (120 )<= 1500
15x <=1500-1320
15x<=180
x <=12
Therefore, we can conclude that 120 students and 20 adults cannot travel for the trip but 120 students can travel with a maximum of 12 adults among with them as it will cost school the trip in the budget.
Learn more about Linear Inequality here brainly.com/question/11897796
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The thing you need to remember is that 25% means 0.25 .
That's the whole problem. The rest is easy.
0.25 x 860 = 215
Adjacent and supplementary :))
Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t
the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)
A. x=2.5t
y=11(t-4)
when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647
answer is 5.18 hours
A.
x=2.5t
y=11(t-4)
B. 5.18 hours
Answer:
answer mine and ill answer yours
Step-by-step explanation:
