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3 years ago

PLEASE I DESPERATELY NEED HELP WITHH THIS!!!!!!! I’ll give brainless and extra points!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Rina8888 [55]3 years ago

8 0

Answer:

1. 4x + 6

2. -15x + 11

5. -x + 4

6. -4x + 7

9. 5x - 2

12. x + 16

Step-by-step explanation:

Remove the parenthesis for each one so everything's out in the open. Next, you group like terms. The numbers with variables on one side, and the other numbers on the other side. For example:

x + 3x - 2 + 8

Then, you combine like terms:

4x + 6

That's mostly how you do each one.

You might be interested in

Which trigonometric ratios are correct for triangle ABC? Check all that apply

sergij07 [2.7K]

Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
ADJ denote the length of the side adjacent to M, and
HYP denote the hypotenuse.

then:

Sin(M) = OPP/HYP
Cos(M)= ADJ/HYPP
Tan(M)=OPP/ADJ

Back to our problem,

using the Pythagorean we can find the length of AB:

$|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 
$

$Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}$
$Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2}$
$Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3}$
$Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2}$
$Tan(B)= \frac{OPP}{ADJ}= \frac{9}{9 \sqrt{3}}= \frac{1}{ \sqrt{3} }= \frac{ \sqrt{3}}{3}$

Answer: 1, 3, 4

5 0

3 years ago

sharon is making greeting cards, each card takes her twenty minutes to make. how many can she complete in two and a half hours?

olga2289 [7]

7 or 8 since 2 and a half hours isnt an even amount of time so thered be an extra 10 minutes

4 0

3 years ago

If 5(3x-7)=20 then what is 6x-8

Alexeev081 [22]

5(3x-7)=20
15x-35=20
15x= 55
x= 55/15
x= 11/3

Plug this x value in.
6(11/3)-8
66/3 -8
22-8
14

Final answer: 14

4 0

4 years ago

olga55 [171]

Gross Domestic Product

7 0

3 years ago

Read 2 more answers

For any two nonzero integers the product and quotient have the same sign.

tamaranim1 [39]

<span>This statement is always true. For any two nonzero integers the product and quotient have the same sign. For example, -2*-3 = 6 and of we see -2/-3, then the result is 2/3. The sign in the result is same after product and quotient, but the result has the same sign.</span>

8 0

3 years ago