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Musya8 [376]
3 years ago
11

One integer is 8​ times another. if the product of the two integers is 288, then find the integers.

Mathematics
1 answer:
Anarel [89]3 years ago
7 0
One integer is x
another integer is y

x=8y
xy=288

(8y)(y)=288
8y^2=288
Divide both sides by 8
y^2= 36
The square root of 36 is 6
y=6

x=8y = 8(6) = 48
x=48
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Factor completely and then place the factors in the proper location on the grid. 36x 2 + 60x + 25
Aleonysh [2.5K]
Since 36x² + 60x + 25 is the perfect square trinomial, we use this formula a² + 2ab + b² = (a + b)². Hence, the solution is (6x + 5)² 
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3 years ago
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If you help me I’ll mark brainliest
Dafna11 [192]

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3 years ago
A figure is composed of a rectangle and a right triangle. What is the area of the figure?
strojnjashka [21]

QUESTION 1

The figure is a tra-pezoid.

The area of a trapezoid is given by the formula;

A=\frac{1}{2}(Sum\:of\:parallel\:sides)\times h

We substitute the values to obtain;

Area=\frac{1}{2}(13.2cm+8.4cm)\times 6cm

Area=\frac{1}{2}(21.6cm)\times 6cm

Area=64.8cm^2

QUESTION 2

The approximate length of the ribbon is equal to the circumference of the circular table cloth.

We can find this by using the formula for calculating the circumference of a circle.

C=2\pi r

where r=3.5ft is the radius of the circular table cloth.

We substitute this value and \pi=3.14 into the formula to get;

C=2(3.14)(3.5)ft

C=21.98ft

The approximate length of the ribbon is 22.0ft to the nearest tenth.

QUESTION 3

Type of quadrilateral:Rectangle

Explanation: A rectangle has 4 angles that are right angles.

The two pairs of opposite sides of a rectangle are also congruent.

QUESTION 4.

The circumference of a semi circle is calculated using the formula;

C=\pi r

where r=12.5cm is the radius of the semicircle.

C=3.14\times 12.5cm

C=39.25cm

QUESTION 5

The area of the entire figure is the area of the semicircle plus the area of the isosceles triangle.

Area=\frac{1}{2}\pi r^2+\frac{1}{2}bh

Area=\frac{1}{2}\times3.14\times12.5^2+\frac{1}{2}\times25\times 24

Area=345.3125+300

Area=645.3125cm^2

Area\approx645cm^2

QUESTION 6

The area of the parallelogram is given by the formula;

A=bh

From the diagram, b=y\:in.,h=3in..

Given, A=23.7 inches squared.

We substitute the values to obtain;

23.7=3y

y=\frac{23.7}{3}

y=7.9in.

QUESTION 7

The area of a rectangle is given by the formula;

Area=l\times b

The area of the bigger rectangle =9\times15=135in^2

The area of the smaller rectangle =8\times 13=104in^2

The area of the  shaded region =135-104=31in^2

5 0
3 years ago
If there is a test with 32 questions and I need a 70% to pass how many can I get wrong and explain why please help 10 POINTS!!!!
maks197457 [2]
WELL 22.5/32 is 70% so to just get that you need to get roughly 9.5 questons wrong
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3 years ago
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Solve for x in the equation 2x2-5x+1=3
Butoxors [25]
2x^2 - 5x + 1 = 3

Subtract 3 from both sides
2x^2 - 5x + 1  - 3 = 3  - 3

2x^2 - 5x - 2 = 0

Use quadratic formula with A = 2,  B =  - 5,   C =  - 2

x =  - b +- sqrt b^2 - 4ac/2a

x =  - ( - 5) +- sqrt (- 5)^2  - 4(2)( - 2)/(2)(2)

x =   5 +- sqrt 41/4

x =  5/4 + 1/4sqrt 41  or x = 5/4 + - 1/4 sqrt 41


Answer:  x = 5/4 + 1/4 sqrt 41
               x = 5/4 +  - 1/4 sqrt 41




Hope that helps!!!!! (D)
5 0
4 years ago
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