Remember
(x^m)/(x^n)=x^(m-n)
7^16/6^12=7^(16-12)=6=7^4
so
7^4=7^-18/?
?=7^?
7^4=7^-18/7^?
7^-18/7^?=7^(-18-?)=7^4
-18-?=4
add 18
-?=22
tmes -1
?=-22
7^-22
answer is C
Answer:
For mean it's the average. You add all three numbers (13, 13 , 10), then you divide it by three since their are three numbers. Average would be 12.
Hope this helps (:
Answer:
The answer to your question is below
Step-by-step explanation:
Functions
f(x) = 12x f⁻¹(x) = 2x
a) f⁻¹(-2) = 2(-2)
f⁻¹(-2) = -4
b) f(-4) = 12x
f(-4) = 12(-4)
f(-4) = -48
c) f(f⁻¹(-2)) =
f(f⁻¹(x)) = 12(2x) = 24x
f(f⁻¹(-2)) = 24(-2) = -48
I think your functions are wrong they must be f(x) = 1/2x f⁻¹(x) = 2x
a) f⁻¹(-2) = 2(-2)
= -4
b) f(-4) = 1/2(-4)
= -2
c) f(f⁻¹(x)) = 1/2(2x)
= x
f(f⁻¹(-2)) = -2
Answer:
a) 658008 samples
b) 274050 samples
c) 515502 samples
Step-by-step explanation:
a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.
So, the number of samples = ⁴⁰C₅ = 658008 samples
b) How many samples of 5 contain exactly one nonconforming chip?
There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways
¹⁰C₁ = 10 ways
then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways
³⁰C₄ = 27405 ways
So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples
c) How many samples of 5 contain at least one nonconforming chip?
The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)
Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples
Total number of samples = 658008
The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples
The answer is Isosceles triangle
