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Arturiano [62]
3 years ago
14

According to the Bureau of Labor Statistics, in 2014, the average annual salary for a Medical Assistant was $31,220. Assuming th

at a Medical Assistants' salary puts them in the 20% income tax bracket, determine the Medical Assistant’s net income (income after taxes are taken out).
Mathematics
2 answers:
OverLord2011 [107]3 years ago
7 0

<u>Answer:</u>

$24,976

<u>Step-by-step explanation:</u>

We know that the average annual salary for a Medical Assistant was $31,220.

So if the Medical Assistants' salary puts them in the 20% income tax bracket, we can find out the net income, after all the taxes are taken out.

If 20% of the Medical Assistants' salary goes to the income tax then the remaining (100-20=) 80% must be his net income.

So calculating the 80% of his annual salary to find his net income:

80% * 31220\\\\=\frac{80}{100} * 31220\\\\=24976

Therefore, a Medical Assistants' net income is $24,976.

Agata [3.3K]3 years ago
4 0

Answer:

24976

Step-By-Step:

Turn the percentage into a decimal then multiply by the amount given.

31,220*.20=6244

Subtract the amount from the original amount.

31,220-6244=24976

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There should be 6 blue bags.

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Q8: Identify the graph of the equation. What is the angle of rotation for the equation?
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Answer:

B. hyperbola, 45°

Step-by-step explanation:

This is rotation in quadratic equations

Perform elimination of xy term

Ax² +B xy+Cy²+Dx+Ey+F=0

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3 years ago
A Luxury of Furniture at a store sells couches for $4,000,Reclining Chairs for $2,040 and loveseats for $2,800. This Luxury line
Kamila [148]
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Reclining Chairs = $ 2 040
=> Loveseats = $2 800
So, the luxury store went on sale that makes each prices divided 4
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8 0
3 years ago
Find all zeros of f(x)=x^4-3x^3+6x^2+2x-60 given that 1+3i is a zero of f(x) ​
Triss [41]

Answer:

The roots of f(x) are: -2, 3, (1+3i) and (1-3i)

Step-by-step explanation:

We are given an expression:

f(x)=x^4-3x^3+6x^2+2x-60

(1+3i) is a root of f(x)

We have to find the remaining roots of f(x).

Since, (1+3i) is a root of f(x),

x-(1+3i)

is a factor of given expression.

Now, we check if (1 - 3i) is a root of given function.

f(x)=x^4-3x^3+6x^2+2x-60\\f(1-3i)=(1-3i)^4-3(1-3i)^3+6(1-3i)^2+2(1-3i)-60\\= (28+96i)-3(-26+18i)+6(-8-6i)+2(1-3i)-60 = 0

Thus, (1-3i) is also a root of given function.

Since, (1-3i) is a root of f(x),

x-(1-3i)

is a factor of given expression.

Thus, we can write:

(x-(1+3i))(x-(1-3i))\text{ is a factor of f(x)}\\x^2-x(1-3i)+x(1+3i)+(1-3i)(1+3i)\text{ is a factor of f(x)}\\x^2-2x+10\text{ is a factor of f(x)}

Dividing f(x) by above expression:

\displaystyle\frac{x^4-3x^3+6x^2+2x-60}{x^2-2x+10} = x^2-x-6

To find the root, we equate it to zero:

x^2-x-6 = 0\\x^2 - 3x+2x-6=0\\x(x-3)+2(x-3)=0\\(x+2)(x-3) = 0\\x = -2, x = 3

Thus, the roots of f(x) are: -2, 3, (1+3i) and (1-3i)

4 0
4 years ago
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