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2 years ago

15

X^5y^4+x^3y^4x 5 y 4 +x 3 y 4

1 answer:

saul85 [17]2 years ago

5 0

Step-by-step explanation:

x+5y×4+x×3y+4

5xy×4x+3xy+4

27xy^2

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A statistician studies the relationship between income and the choice of individuals to attend college. He notices that during a

Gnoma [55]

The conclusion is is misleading because the extraneous variable, cost of tuition was not accounted for in the experiment.

<h3>What are the variables in this experiment?</h3>

The independent variable is the variable that the person carrying out an experiment changes or manipulates. This variable is income. The dependent variable is the variable that is being measured in an experiment. This variable is college enrolment.

The extraneous variable is the variable that is not been researched in the experiment but it has the potential to influence the results of the experiment. This variable is the cost of tuition.

To learn more about independent variables, please check: brainly.com/question/26287880

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6 0

1 year ago

tyler read 15 pages of a book. Ann read 9 pages of the same book. Did Tyler read 4 more pages than Ann? Explain

Slav-nsk [51]

No because fifteen minus nine is six, so Tyler read six more pages than Ann.

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3 years ago

NEED HELP ASAPP PLEASEE

mart [117]

Answer:

22.25

Step-by-step explanation:

take the two values away

the sector is the full address , the triangle is in it. the segment is the bit left near the circumference

5 0

2 years ago

Anne, Barry, and Cathy enter a coffee shop. Anne orders two coffees, one juice, and two doughnuts and pays $7.50. Barry orders o

Evgesh-ka [11]

Answer:

Coffee = $2.00

Juice = $1.50

Doughnut = $1.00

Step-by-step explanation:

Given

Let:

$c = coffee\\ j= juice\\ d = doughnut$

So, we have:

Anna

$2c + j + 2d = 7.50$

Barry

$c + 3d = 5.00$

Cathy

$3c + j + 4d = 11.50$

Required

The price of each

We have:

$2c + j + 2d = 7.50$

$c + 3d = 5.00$

$3c + j + 4d = 11.50$

Make c the subject in: $c + 3d = 5.00$

$c = 5.00 - 3d$

Substitute $c = 5.00 - 3d$ in $2c + j + 2d = 7.50$ and $3c + j + 4d = 11.50$

$2c + j + 2d = 7.50$

$2[5.00 - 3d] + j + 2d = 7.50$

$10.00 - 6d+ j + 2d = 7.50$

Make j the subject

$j = 7.50 - 10.0 +6d - 2d$

$j = -2.50 +4d$

$3c + j + 4d = 11.50$

$3[5.00 - 3d] + j + 4d = 11.50$

$15.00 - 9d + j + 4d = 11.50$

Make j the subject

$j = 11.50 - 15.00 + 9d -4d$

$j = -3.50 + 5d$

So, we have:

$j = -3.50 + 5d$ and $j = -2.50 +4d$

Equate both values of j

$-3.50 + 5d = -2.50 + 4d$

Collect like terms

$5d - 4d = 3.50 -2.50$

$d = 1.00$

Substitute $d = 1.00$ in $j = -3.50 + 5d$

$j = -3.50 + 5d$

$j = -3.50 + 5 * 1.00$

$j = -3.50 + 5.00$

$j = 1.50$

To solve for c, we substitute $d = 1.00$ in $c + 3d = 5.00$

$c + 3 * 1.00 =5.00$

$c + 3.00 =5.00$

Solve for c

$c =- 3.00 +5.00$

$c =2.00$

7 0

2 years ago

all possible numbers that when replaced with the "?" in the set of ordered pairs {(3, 4), (–2, –5), (?, 0)} would create a funct

irina [24]

? can be any number except for 3 or -2 as it is already used in (3,4), (-2,-5)

4 0

3 years ago