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3 years ago

15

What is the square root of

lt=" \sqrt{163} " align="absmiddle" class="latex-formula">

1 answer:

crimeas [40]3 years ago

5 0

Hi,

$\sqrt{163} = 12.76$

There are no other simple steps to reduce the square root of one hundred and sixty-three.

The actual square root value is ≈12.767145334803704

But we have taken only significant figures and it is as 12.76.

Hope it helps! :)

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Answer:

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Step-by-step explanation:

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Answer:

$P(\bar X$

And we can solve this using the following z score formula:

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And if we use this formula we got:

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So we can find this probability equivalently like this:

$P( Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(63.6,2.5)$

Where $\mu=63.6$ and $\sigma=2.5$

We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

We want this probability:

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And we can solve this using the following z score formula:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we use this formula we got:

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