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3 years ago

Maddox decided to play a game

Mathematics

1 answer:

Jet001 [13]3 years ago

4 0

Answer:

Each student would get 36 candies is their goddy bag.

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Explain how you write products when there are not enough digits in the product to place a decimal point

Anni [7]

If you there isn't enough digits to place, just add zeroes to product to make it a full product or don't even use a decimal point at all.

6 0

3 years ago

.Solve the system of equations. Use elimination

Elina [12.6K]

Answer:

a) (-9,3)

Step-by-step explanation:

x + 2y = -3

- (x - y = -12)

<u />

x + 2y = -3

3y = 9

y = 3

x - y = -12

x- 3 = -12

x= - 9

(-9, 3)

6 0

3 years ago

In the number 3,335 how many times greater is the value of the 3 on the left than the 3 on the right

AlekseyPX

Answer:

(If they were talking about 3,335, then) 100 times greater

(If they were talking about 3,335 then) 10 times greater

Step-by-step explanation:

When you visualize it, ignore the other numbers and think of only the threes.

Count how many spaces/places they are from each other, and that's how many 0s you should put after a 1 as your answer.

Same as decimal moving and multiplying by 10's.

8 0

3 years ago

Write y+2=13x in standard form.

Afina-wow [57]

24 I hope this helpsssss :):):)

7 0

3 years ago

Sam entered three functions into a graphing calculator, y1 = x + 2, y2 = x2 + 2, and y3 = 2x. A portion of the table created by

V125BC [204]

For this case we have the following functions:
$y1 = x + 2

y2 = x ^ 2 + 2

y3 = 2 ^ x$

When x = 0 we have:
For y1:
$y1 = 0 + 2

y1 = 2$
For y2:
$y2 = 0 ^ 2 + 2

y2 = 0 + 2

y2 = 2$
Therefore, we have to:
$y1 = y2
$

When x = 5 we have:
For y2:
$y2 = 5 ^ 2 + 2

y2 = 25 + 2

y2 = 27$
For y3:
$y3 = 2 ^ 5

y3 = 32$
Therefore, we have to:
$y2 \ \textless \ y3
$

When x = -1 we have:
For y1:
$y1 = -1 + 2

y1 = 1$
For y2:
$y2 = (-1) ^ 2 + 2

y2 = 1 + 2

y2 = 3
$
For y3:
$y3 = 2 ^ {-1}

y3 = 1/2

y3 = 0.5$
Therefore, we have to:
$y3 \ \textless \ y1 \ \textless \ y2
$

Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2

4 0

3 years ago