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hammer [34]
2 years ago
6

A coin is weighted so that the probability of heads is 0.64. On average, how many coin flips will it take for the tails to first

appear
Mathematics
1 answer:
gladu [14]2 years ago
8 0

Answer:

1.563

Step-by-step explanation:

Given :

Probability of head, p = 0.64

Number of flips it would take for tail to appear first :

Treatting the question as a geometric function :

Using the relation :

1 / p

Expected number of flips until first tail :

1 / P = 1/ 0.64 = 1.5625

E(x) = expected number of flips until first tail = 1.563

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Okay! Time to use the Pythagoras theorem.

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3 years ago
Alandra's rectangular cake pan is 33cm by 23 cm. She has enough cake batter to fill it to a depth of 3 cm. Instead, Alandra want
Alisiya [41]

Answer:

Alandra can fill 60 whole cones

Step-by-step explanation:

The volume of a rectangular prism is V = L × W × H, where

  • L is its length
  • W is its width
  • H is its height

The volume of the cone is V = \frac{1}{3} π r² h, where

  • r is the radius of its base
  • h is its height

∵ Alandra's rectangular cake pan is 33 cm by 23 cm

∴ L = 33 cm and W = 23 cm

∵ She has enough cake batter to fill it to a depth of 3 cm.

∴ H = 3 cm

→ Find the volume of the batter using the 1st rule above

∵ V = 33 × 23 × 3

∴ V = 2277 cm³

∵ Alandra wants to pour the batter into ice cream cones

∵ She plans to fill each cone to a depth of 9 cm with a diameter of 4 cm

∴ h = 9 cm

∵ r = \frac{1}{2} diameter = \frac{1}{2} (4)

∴ r = 2 cm

→ Substitute them in the 2nd rule above to find the volume of each cone

∵ V = \frac{1}{3} (π) (2)² (9)

∴ V = 12π cm³

→ To find the number of cones divide the volume of the batter by

   the volume of each cone

∵ Number of cones = 2277 ÷ 12π

∴ Number of cones = 60.3993

→ We will take the whole number only because we need the whole cones

∴ Alandra can fill 60 whole cones

6 0
3 years ago
f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans
Kruka [31]

Answer:

\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558

Step-by-step explanation:

We want to find the Riemann sum for \int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)

where \Delta{x}=\frac{b-a}{n}.

Step 1: Find \Delta{x}

We have that a=0, b=\frac{3\pi }{4}, n=6

Therefore, \Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}

Step 2: Divide the interval \left[0,\frac{3 \pi}{4}\right] into n = 6 sub-intervals of length \Delta{x}=\frac{\pi}{8}

a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b

Step 3: Evaluate the function at the left endpoints

f\left(x_{0}\right)=f(a)=f\left(0\right)=3=3

f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386

f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964

f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527

f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0

f\left(x_{5}\right)=f\left(\frac{5 \pi}{8}\right)=- 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=-1.14805029709527

Step 4: Apply the Left Riemann Sum formula

\frac{\pi}{8}(3+2.77163859753386+2.12132034355964+1.14805029709527+0-1.14805029709527)=3.09955772805315

\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558

5 0
3 years ago
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