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hammer [34]
2 years ago
6

A coin is weighted so that the probability of heads is 0.64. On average, how many coin flips will it take for the tails to first

appear
Mathematics
1 answer:
gladu [14]2 years ago
8 0

Answer:

1.563

Step-by-step explanation:

Given :

Probability of head, p = 0.64

Number of flips it would take for tail to appear first :

Treatting the question as a geometric function :

Using the relation :

1 / p

Expected number of flips until first tail :

1 / P = 1/ 0.64 = 1.5625

E(x) = expected number of flips until first tail = 1.563

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Step-by-step explanation:

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2 years ago
Rewrite this radicand as two factors, one of which is a perfect square.
seropon [69]

Answer:

2 \sqrt{15}

Step-by-step explanation:

1) rewrite 60 as it's prime factors.

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2) group the smae prime factors into pairs.

\sqrt{(2 \times 2)}  \times 3 \times 5

3) Rewrite each pair in exponent form.

\sqrt{ {2}^{2} \times 3 \times 5 }

4) use this role:

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5) Simplify.

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So, therefor, the answer is option 1.

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3 years ago
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2 years ago
Suppose Z Varies directly with x and inversely with y, where x = 16, y = 4, when z = 32...............
Greeley [361]
A.)
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b.)
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1 Without graphing, determine the characteristics of the graph.
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