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fgiga [73]
3 years ago
6

The scope of a variable declared within a for() loop is:

Computers and Technology
1 answer:
Leni [432]3 years ago
5 0

Answer:

a

Explanation:

The variable declared in the for is accessible only within the for loop  and it goes out of scope once the loop get end

eg : for(int i=1;i<=10,i++) // variable i is declared

{

// variable i is visible only in this block,

}

//After this the variable i goes out of scope

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List the general steps that are used to configure a soho router and set up the network
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What is the meaning of ethics? Check all of the boxes that apply
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Write a program that uses the function isPalindrome given in Example 6-6 (Palindrome). Test your program on the following string
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Answer:

#include <bits/stdc++.h>

using namespace std;

bool isPalindrome(string str)

{

   char a,b;

int length = str.length();

for (int i = 0; i < length / 2; i++)

{

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   b=tolower(str[length-1-i]);

   if (b != a )

return false;

}

return true;

   

}

int main() {

   string t1;

   cin>>t1;

   if(isPalindrome(t1))

   cout<<"The string is Palindrome"<<endl;

   else

   cout<<"The string is not Palindrome"<<endl;

return 0;

}

Output:-

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The string is Palindrome

Enter the string

abba

The string is Palindrome

Enter the string

22

The string is Palindrome

Enter the string

67876

The string is Palindrome

Enter the string

444244

The string is not Palindrome

Explanation:

To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.

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