Question

You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. You are also given a variable m of type Comparable. Write the code needed to assign to m a reference to the median value of the array. (You may modify the array x by rearranging its elements.)NOTE: The median of a set of values is the value in the set such that there are as many values that are greater as there are that are less. For purposes of THIS exercise, if the array has an even number of members, the median is the greater of the two middle values.
EXAMPLE 1: Given "bob" "carol" "ted" "alice" "fred" the median is "carol" because there are "bob" and "alice" are less than "carol" and "fred" and "ted" are greater.
EXAMPLE 2: Given "bob" "carol" "ted" "alice" "fred" "sue", the middle two values are "carol" and "fred" and so in THIS exercise we would consider the greater to be the median.

Answer 1

Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

m = x[x.length/2];