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Airida [17]
3 years ago
9

What type of number can be written as a fraction p%q where p and q aré integers and q is not equal to zero

Mathematics
1 answer:
MatroZZZ [7]3 years ago
7 0
Hi there!

The correct answer is Rational Number.

\bf{EXPLANATION} :-

Rational Number is any number that can be expressed as the quotient or fraction p/q of two integers, a numerator " p " and a non-zero denominator " q ".

~ Hope it helps!
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Please help dont know how
stiks02 [169]

Answer:

90 and 270 maybe neg 270

Step-by-step explanation:

5 0
2 years ago
Simplify (2/9)^3<br> A.6/9<br> B.8/729<br> C.2/720
saw5 [17]

<u>Answer:</u>

\frac{8}{729}


<u>Explanation:</u>

Before we begin, remember that:

(\frac{a}{b})ⁿ = \frac{a^n}{b^n}


This means that power is distributed in case of division


The given is:

(\frac{2}{9} )^3


Applying the above rule, we would get:

(\frac{2}{9} )^3 = \frac{2^3}{9^3} = \frac{2*2*2}{9*9*9} = \frac{8}{729}


Hope this helps :)


8 0
3 years ago
Mr. Duval bought 21 calculators for his classroom. The total cost was
Olenka [21]

Answer:

$6.75 each

Step-by-step explanation:

141.75 decided by the 21 calculators gets a grand total of $6.75 each

7 0
3 years ago
The goal of the fundraiser to make than $150
Sergio039 [100]

Answer:

Step-by-step explanation:

Making more than $150

Let the amount to be made be x.

Then: x+$150 will be the amount needed to be made

7 0
3 years ago
If the length of AB is 10 cm from the center and has a length of 12, find the approximate length from the center to CD.​
Lynna [10]

<u>Given</u>–

AB = 12 Cm

CD = 14 Cm

PO = 10 Cm

AP = 1/2 × 12 = 6 Cm

<u>Construction</u>–

Draw NO such that it is the perpendicular bisector of CB.

Hence,

ND = 1/2 × 14 = 7 Cm

To Find,

Measure of NO

<u>Solution</u>,

Here, PO Perpendicular to AB

Hence, APO is a right-angled triangle–

AO² = PO² + AP²

Or, AO² = 10 ² + 6 ²

Or, AO² = 36 + 100

Or, AO = √136 Cm

Or, AO = 11.66 Cm

Also, AO = OD = 11.66 Cm

( Radius of the same circle )

Now, in triangle OND,

OD² = ON² + ND ²

Or, 11.66 ² = ON² + 7²

Or, 136 = ON² + 49

Or, ON ² = 136 – 49

Or, ON ² = 87

Or, ON ² = √87

Or, ON = 9.3 Cm

Therefore, the appropriate length from center to CD is 9.3 Cm.

4 0
3 years ago
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