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VLD [36.1K]
4 years ago
11

One serving of a certain brand of yogurt contains 7g of fat. The​ low-fat version contains ​38.25% less fat per serving. How man

y grams of fat does one serving the​ low-fat yogurt​ contain?
Mathematics
1 answer:
Dafna1 [17]4 years ago
6 0

Answer:

7g-100%

x-38,25

38,25*7:100=2,6775g

7g-2,6775g=4,4325g

Step-by-step explanation:

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Circumference of the circle
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Step-by-step explanation:

The formula for calculating a circle's circumference is πd, where π is an irrational number (3.14....) and d is the diameter of the circle.

In the circle with diameter 19.5cm, the circumference is around 3.14 * 19.5cm = 61.23cm. (A)

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3 years ago
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Need help<br> Solve 3x−5 = 9.
kipiarov [429]
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I don't know how to solve this problem ​
Rom4ik [11]

<em><u>Before you read this!!</u></em><em> To me, it looks like 8 is the entire length of lineJL, but it may only be the length of lineJM. I've written the steps for lineJL=8 NOT lineJM=8. If this is not the case and 8 is only the length of lineJM let me know so I can fix my answer!</em>

Step-by-step explanation:

The area of a triangle is A=1/2(b)(h)

B=base

H=height

Your height is found in the line in the middle of the triangle, for you it is 6.

The base is the long bottom line on the triangle (lineJL), for you it is 8.

So let's put it in.

A=1/2(8)(6)

A=24sq units (C)

4 0
3 years ago
13. Determine whether B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} is a basis of R3.
Sholpan [36]

Answer:  Yes, the given set of vectors is a basis of R³.

Step-by-step explanation:  We are given to determine whether the following set of three vectors in R³ is a basis of R³ or not :

B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} .

For a set to be a basis of R³, the following two conditions must be fulfilled :

(i) The set should contain three vectors, equal to the dimension of R³

and

(ii) the three vectors must be linearly independent.

The first condition is already fulfilled since we have three vectors in set B.

Now, to check the independence, we will find the determinant formed by theses three vectors as rows.

If the value of the determinant is non zero, then the vectors are linearly independent.

The value of the determinant can be found as follows :

D\\\\\\=\begin{vmatrix} -1& 1 & -1\\ 1 & 0 & 2\\ 1 & 1 & 0\end{vmatrix}\\\\\\=-1(0\times0-2\times1)+1(2\times1-1\times0)-1(1\times1-0\times1)\\\\=(-1)\times(-2)+1\times2-1\times1\\\\=2+2-1\\\\=3\neq 0.

Therefore, the determinant is not equal to 0 and so the given set of vectors is linearly independent.

Thus, the given set is a basis of R³.

5 0
3 years ago
Find the sum to infinity of a geometric series having a second term of -9 and fifth term of 1/3 g
Eduardwww [97]

Answer:

S infinity= -51/4

Step-by-step explanation:

First term

ar= -9

Fifth term

ar⁴= 1/3

Solving for the value of the r and a

ar= -9

ar⁴= 1/3

Dividing each other

r³=1/3 * -1/9

r³=-1/27

r= 3√-1/27

r= -1/3

Solving for a

ar= -9

a(-1/3)= 9

a= 9*-3

a= -27

Sum of a go to infinity is given by the formula

S infinity= a/(1-r)

S infinity= -27/(1-(-1/3))

S infinity= -27/(1+1/3)

S infinity= -27 * 3/4

S infinity= -51/4

5 0
3 years ago
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