Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
Answer:
The pattern is + 10.
Step-by-step explanation:
13 + 10 = 23
23 + 10 = 33
33 + 10 = 43
...and so on.
I hope this helped! :-)
The square root of 58 is around 7.6
The entire number is, 7.61577310586...
Answer:
x <5
Step-by-step explanation:
2(4 x + 3) < 5 x + 21
Distribute
8x +6 < 5x +21
Subtract 5x from each side
8x -5x +6 < 5x-5x+21
3x +6 < 21
Subtract 6 from each side
3x+6-6 <21-6
3x <15
Divide each side by 3
3x/3 <15/3
x <5