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kicyunya [14]
3 years ago
11

A symmetrical binomial distribution with large sample size can be approximated by a __________

Mathematics
1 answer:
sweet [91]3 years ago
7 0
Typical distribution?
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The following data points represent the volume
svetoff [14.1K]

Answer:

The missing volume of gas is 6 liters

Step-by-step explanation:

The following data points represent the volume  of gas in each race car driver's tank (in liters):

4,5, 13, ?

Let the missing value be x

Data : 4,5,13,x

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}

7 = \frac{4+5+13+x}{4}

7 \times 4=4+5+13+x

28=22+x

28-22=x

6=x

Hence The missing volume of gas is 6 liters

3 0
3 years ago
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Jabari needs 575 tickets to get the prize he wants at the arcade .he already has 210 tickets and can earn 31 tickets each time h
EleoNora [17]

Answer:

12

Step-by-step explanation:

575 - 210 = 365

365/31 = 11.7741935484

if he plays 11 games, that's not enough. so he has to play 12 games

HOPE THIS HELPS!!!!!

5 0
3 years ago
Solve the equation below for the variable "x". *<br> - 2x + 10 = 8
Brums [2.3K]

Answer:

x = 1

Step-by-step explanation:

Subtract 10 from 8 to get -2. Then divide -2x by itself so it will cancel out. Whatever you do to one side of the equation, do to the other so divide -2 by -2 to get your answer of 1

3 0
3 years ago
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Which monomials are divisible by 5x
ValentinkaMS [17]
What is a monomials again?
7 0
3 years ago
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Emily wants to watch her intake of fat per day.
AfilCa [17]

Answer:

One variable equation that is (4800/x) represents percentage of Emily's dinner fat intake compared to total daily allowance of x gram.

Step-by-step explanation:

lets assume the variable for total daily allowance

lets say total daily allowance of fat = x grams

Fat consumed at dinner = 48 grams

Fat consumed at dinner in percentage = (Fat consumed at dinner/total daily allowance of fat) × 100

= (48 grams/x grams)×100=(4800/x)%

so (4800/x)%  

So one variable equation that is (4800/x) represents percentage of Emily's dinner fat intake compared to total daily allowance of x gram.

lets take one example

lets says total daily allowance of fat for Emily = 100gm

so from derived equation that is 4800/x , we can get required percentage by putting x =  total daily allowance of fat = 100gm

=4800/100 = 48%.

you can change value of variable x according to total daily allowance and get the required dinner intake percentage by equation 4800/x.


6 0
3 years ago
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