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Bess [88]
3 years ago
8

An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number

of key rings is given by , where n is the number of key rings in thousands. Find the number of key rings sold on a particular day when the total profit is $5,000.
n^2-2n-3
Mathematics
1 answer:
vovangra [49]3 years ago
3 0

Answer:

The number of key rings sold on that day is 4000 key rings

Step-by-step explanation:

* Lets explain the information in the problem

- The profit earned (in thousands of dollars) per day by selling n number

  of key rings is given by the function P(n) = n² - 2n - 3, where n is the

  number of key rings in thousands and P is the profit in thousands

  for one day

- On a particular day the total profit is $5,000

∵ 5000 = 5 in thousands

∵ The function P(n) is the profit of n key ring in thousands

∴ P(n) = 5

- Lets solve the function to find the number of key rings

∵ P(n) = n² - 2n - 3

∴ 5 = n² - 2n - 3 ⇒ subtract 5 from both sides

∴ 0 = n² - 2n - 8 ⇒ factorize it

∵ n² = n × n ⇒ 1st terms in the 2 brackets

∵ -8 = -4 × 2 ⇒ 2nd terms in the 2 brackets

∵ n × -4 = -4n ⇒ nears

∵ n × 2 = 2n ⇒ extremes

∵ -4n + 2n = -2n ⇒ the middle term

∴ (n - 4)(n + 2) = 0 ⇒ equate each bracket by 0 to find n

∴ n - 4 = 0 ⇒ add 4 to both sides

∴ n = 4 key ring in thousands = 4000 key rings

- OR

∴ n + 2 = 0 ⇒ subtract 2 from both sides

∴ n = -2 ⇒ we will refused this value because number of key rings

   must be positive

∴ The number of key rings sold on that day is 4000 key rings

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7(7) - 7 = 42

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A string of holiday lights at a store has three colors that flash at different times. Red lights flash every fifth second. Blue
-Dominant- [34]

Answer:

60

Step-by-step explanation:

You need the least common multiple of 5, 3, and 4.

5 = 5, 10, 15, 20, 25... 60

3= 3, 6, 9...60

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4 0
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Peg and Larry purchased “no contract” cell phones. Pegs phone costs $25 plus $0.25 per minute. Larry’s phone cost $35 plus $0.20
marissa [1.9K]
Let x be the number of minutes Peg and Larry used their phones. So their costs can be written as:

Cost of Peg's Phone usage = 25 + 0.25x
Cost of Larry's Phone usage = 35 + 0.20x

We are to find when the Peg's phone will be more than Larry's phone. We can set up the inequality as:

25 + 0.25x > 35 + 0.20x

Re-arranging the inequality

0.25x - 0.20x > 35 - 25

0.05x > 10

x > 10/0.05

x > 200

Thus, Pag's phone will cost more if the number of minutes of phone usage is more than 200
5 0
3 years ago
Trade barriers discourage consumers from buying imported goods because barriers can __________. A. make imports much more common
Trava [24]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
In ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45. What is the value of the cosine of ∠X to the nearest hundredth?
kotegsom [21]

The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

Step-by-step explanation:

The given is,

                   In ΔWXY, ∠Y=90°

                        XW = 53

                         YX = 28

                        WY = 45

Step:1

             Ref the attachment,

             Given triangle XWY is right angled triangle.

             Trigonometric ratio's,

                              Cos ∅  = \frac{Adj}{Hyp}    

             For the given attachment, the trigonometric ratio becomes,

                              Cos ∅  = \frac{XY}{XW}.....................................(1)

             Let, ∠X = ∅

             Where, XY = 28

                         XW =  53

             Equation (1) becomes,

                                 Cos ∅  = \frac{28}{53}

                                 Cos ∅ = 0.5283

                                        ∅ = cos^{-1} (0.5283)

                                        ∅ = 58.109°

Result:

          The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

             

4 0
3 years ago
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