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Bess [88]
3 years ago
8

An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number

of key rings is given by , where n is the number of key rings in thousands. Find the number of key rings sold on a particular day when the total profit is $5,000.
n^2-2n-3
Mathematics
1 answer:
vovangra [49]3 years ago
3 0

Answer:

The number of key rings sold on that day is 4000 key rings

Step-by-step explanation:

* Lets explain the information in the problem

- The profit earned (in thousands of dollars) per day by selling n number

  of key rings is given by the function P(n) = n² - 2n - 3, where n is the

  number of key rings in thousands and P is the profit in thousands

  for one day

- On a particular day the total profit is $5,000

∵ 5000 = 5 in thousands

∵ The function P(n) is the profit of n key ring in thousands

∴ P(n) = 5

- Lets solve the function to find the number of key rings

∵ P(n) = n² - 2n - 3

∴ 5 = n² - 2n - 3 ⇒ subtract 5 from both sides

∴ 0 = n² - 2n - 8 ⇒ factorize it

∵ n² = n × n ⇒ 1st terms in the 2 brackets

∵ -8 = -4 × 2 ⇒ 2nd terms in the 2 brackets

∵ n × -4 = -4n ⇒ nears

∵ n × 2 = 2n ⇒ extremes

∵ -4n + 2n = -2n ⇒ the middle term

∴ (n - 4)(n + 2) = 0 ⇒ equate each bracket by 0 to find n

∴ n - 4 = 0 ⇒ add 4 to both sides

∴ n = 4 key ring in thousands = 4000 key rings

- OR

∴ n + 2 = 0 ⇒ subtract 2 from both sides

∴ n = -2 ⇒ we will refused this value because number of key rings

   must be positive

∴ The number of key rings sold on that day is 4000 key rings

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An item cost 50 is marked up 20% off.Sales tax for the item is 8%.What is the final price including tax?
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3 years ago
There are 81 people protesting the destruction of the rain forests. There are 36 ​males, 23 of whom are​ students, and 18 female
Leviafan [203]

Answer:

27

Step-by-step explanation:

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2 years ago
An elementary school is offering 3 language classes: one in Spanish, one in French,and one in German. The classes are open to an
Alona [7]

Answer:

A. 0.5

B. 0.32

C. 0.75

Step-by-step explanation:

There are

  • 28 students in the Spanish class,
  • 26 in the French class,
  • 16 in the German class,
  • 12 students that are in both Spanish and French,
  • 4 that are in both Spanish and German,
  • 6 that are in both French and German,
  • 2 students taking all 3 classes.

So,

  • 2 students taking all 3 classes,
  • 6 - 2 = 4 students are in French and German, bu are not in Spanish,
  • 4 - 2 = 2 students are in Spanish and German, but are not in French,
  • 12 - 2 = 10 students are in Spanish and French but are not in German,
  • 16 - 2 - 4 - 2 = 8 students are only in German,
  • 26 - 2 - 4 - 10 = 10 students are only in French,
  • 28 - 2 - 2 - 10 = 14 students are only in Spanish.

In total, there are

2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.

The classes are open to any of the 100 students in the school, so

100 - 50 = 50 students are not in any of the languages classes.

A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

\dfrac{50}{100} =0.5

B. If a student is chosen randomly,  the probability that he or she is taking exactly one language class is

\dfrac{8+10+14}{100}=0.32

C. If 2 students are chosen randomly,  the probability that both are not taking any language classes is

0.5\cdot 0.5=0.25

So,  the probability that at least 1 is taking a language class is

1-0.25=0.75

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