All categories

3 years ago

Multiply the following using the vertical multiplication method: 3x2 + 5x + 1 x x2 - 2x + 4

Mathematics

1 answer:

Oksanka [162]3 years ago

4 0

Answer:

Step-by-step explanation:

the answer is b

You might be interested in

When this 3-digit number is rounded to the nearest ten, the sum of its digits is 16. The hundreds digit of this number is 8 and

kramer

Answer:

835

Step-by-step explanation:

We know that the hundreds is 8 and the ones is 5 so the sum needed is 16-(8+5), which equals 3 :)

6 0

3 years ago

Read 2 more answers

A car’s original price was $26,500. Mr. Thomas paid $18,815. What percent discount did Mr. Thomas receive on the car?

Grace [21]

B. He received 29% discount on the car.<span />

6 0

3 years ago

Read 2 more answers

Terry needs to carry a pole that

Natasha2012 [34]

Answer:

Yes, The pole will fit through the door because the diagonal width of the door is 10.8 feet, which is longer than the length of the pole.

Step-by-step explanation:

Using the Pythagorean Theorem, ( $a^2+b^2=c^2$ ) we can measure the hypotenuse of a right triangle. Since the doorway is a rectangle, and a rectangle cut diagonally is a right triangle, we can use Pythagorean Theorem to measure the diagonal width of the doorway.

Plug in the values of the length and width of the door for a and b. The c value will represent the diagonal width of the doorway:

$6^2+9^2=c^2$

$36+81=c^2$

$117=c^2$

Since 117 is equal to the value of c multiplied by c, we must find the square root of 117 to find the value of c.

$\sqrt{117} =10.8$

$10.8=c$

Yes, The pole will fit through the door because the diagonal width of the door is 10.8 feet, which is longer than the length of the pole, measuring 10 feet.

7 0

3 years ago

Can someone help me?

Lana71 [14]

Answer:

I'm not sure from my answer but I'm going to try

A = { a^2 - 4 = 0 }

A = { a^2 = 0+ 4 }

A = { a^2 = 4}

Take root of both sides

A = {a = 2}

A = {2}

B = { -2, -1, 0, 1, 2}

C = { 1, 2, 3, 4, 5, 6,7}

i) A\B

= {2} \ {-2,-1,0,1,2}

= ⌀ ( "null set" )

ii) (A\B) \C

= ( {2} \ {-2,-1,0,1,2} ) \ C

= ⌀ \ C

= ⌀ \ { 1, 2, 3, 4, 5, 6,7}

= ⌀ ( "null set" )

iii) (A ∪ B) \ C

= ( { 2 } ∪ { -2, -1, 0, 1, 2} ) \ C

= { -2, -1, 0, 1, 2} \C

= { -2, -1, 0, 1, 2} \ { 1, 2, 3, 4, 5, 6,7}

= { -2, -1, 0 }

iv) ( A\B) ∩ ( A\C)

= ( { 2 } \ {-2,-1,0,1,2} ) ∩ ( { 2 } \ { { 1, 2, 3, 4, 5, 6,7} )

= ⌀ ∩ ⌀

= ⌀

v) ( A ∩ B ) \ C

= ( { 2 } ∩ { -2, -1, 0, 1, 2 } ) \ C

= { 2 } \ { 1, 2, 3, 4, 5, 6, 7 }

= ⌀ "null set"

7 0

3 years ago

If 270°<θ<360°, and tan⁡ θ= - 1/2, what is the value of tan⁡(−θ)?

stiv31 [10]

Check the picture below.

let's recall that once we move an angle in the opposite direction of the 0-line or x-axis, we end up with a negative counterpart angle.

since we know that θ is on the IV Quadrant, then its negative counterpart must be across the line, and tangent is negative on the IV Quadrant, and positive on the I Quadrant.

4 0

3 years ago