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enyata [817]
3 years ago
6

A ball on the end of a string is spinning around a circle with a radius of 5 centimeters. If in 3.1 seconds a central angle of p

ie/18
radian has been covered, what is the angular speed of the ball?
Mathematics
1 answer:
andriy [413]3 years ago
7 0
Angular speed is radians per second.

It covers pi/18 in 3.1 seconds.

Angular speed = (pi/18)/3.1
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Eliminate the parameter. x = t2 + 1, y = t2 - 1
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\bf \begin{cases}
x=t^2+1\implies x-1=\boxed{t^2}\\
y=t^2-1\\
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y=\boxed{x-1}-1\\
y=x-2
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3 years ago
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Myra owns a car service that charges a $5 flat rate and an additional $0.50 per mile, which is represented by the equation y = 0
klasskru [66]
Just substitute
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Points A and B are on the different sides of a line 1, the distance between point A and the line lis 10 in, the distance between
givi [52]

Answer: Distance between O and the line 1 is 3 inches.

Explanation:

Since we have given that

Distance between point A and the line 1 = 10 inches

Distance between point B and the line 1 = 4 inches

Total length of segment AB is given by

10+4=14\ inches

Since O is midpoint of the line segment AB.

so, AO is given by

\frac{14}{2}=7\ in.

Now, Distance between O and the line 1 is given by

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Hence, Distance between O and the line 1 is 3 inches.

7 0
3 years ago
I'm confused on this<br>(this is 12 year old math) ​
Gemiola [76]

Answer: the top box can be the linear equation y=40x+15 and the bottom box is 40

Step-by-step explanation:

If you swim 15 more minutes than your friend and your swam 55 minutes, that means your friend only swam 40 minutes. The set amount of time that your friend swims for <em>x</em> is 40 minutes. So the additional time you swim is <em>b</em>, 15 minutes.

7 0
2 years ago
Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a
kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be representedh(t)=-16t^2+20t.

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?  

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}

\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}

\text{Average rate of change}=\frac{6}{\frac{1}{2}}

\text{Average rate of change}=\frac{2\cdot 6}{1}

\text{Average rate of change}=12

Therefore, Spot's average rate of ascent is 12 feet per second.

3 0
3 years ago
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