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3 years ago

6

A ball on the end of a string is spinning around a circle with a radius of 5 centimeters. If in 3.1 seconds a central angle of p

ie/18
radian has been covered, what is the angular speed of the ball?

1 answer:

andriy [413]3 years ago

7 0

Angular speed is radians per second.

It covers pi/18 in 3.1 seconds.

Angular speed = (pi/18)/3.1

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If he has his choices narrowed down to 77 hip-hop, 55 jazz, 77 pop, and 88 blues songs, and he wants to play all 55 jazz songs,

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1.27 × (10^73)

Step-by-step explanation:

55!

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3 years ago

You are painting a rectangular tabletop. The length of the table top is 6 inches less than 3 times the

dedylja [7]

Answer:

A

Step-by-step explanation:

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2 years ago

Mai biked 5 1/4 miles today, and Noah biked 2 1/2 miles. How many times the length of Noah’s bike ride was Mai’s bike ride?

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Answer:

The length of Mai's bike ride was 2.1 times the length of Noah's ride.

Step-by-step explanation:

Mai biked 5 1/4 miles today

So he biked, in miles:

$5 + \frac{1}{4} = \frac{5*4 + 1}{4} = \frac{20+1}{4} = \frac{21}{4}$

Noah biked 2 1/2 miles.

So, in miles, he biked:

$2 + \frac{1}{2} = \frac{2*2 + 1}{2} = \frac{4+1}{2} = \frac{5}{2}$

How many times the length of Noah’s bike ride was Mai’s bike ride?

We divide the Mai distance by Noah's distance. In a division of fractions, we multiply the numerator by the inverse of the denominator. So

$\frac{\frac{21}{4}}{\frac{5}{2}} = \frac{21}{4} \times {2}{5} = \frac{21*1}{2*5} = \frac{21}{10} = 2.1$

The length of Mai's bike ride was 2.1 times the length of Noah's ride.

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2 years ago

A car was sold in 1990. The value of the car

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2 years ago

An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

$y^2=1-3x^2$

$3x^2+y^2=1$

$\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1$

therefore it is a vertical ellipse

thus a=1

$b=\frac{1}{\sqrt{3}}$

eccentricity of Ellipse

$e^2=1-\frac{b^2}{a^2}$

$e^2=1-\frac{1}{(\sqrt{3})^2}$

$e^2=1-\frac{1}{3}$

$e^2=\frac{2}{3}$

$e=\sqrt{\frac{2}{3}}$

Focii are $(0,ae)$ and $(0,-ae)$

$ae=1\times \sqrt{\frac{2}{3}}$

thus focii are $(0,\sqrt{\frac{2}{3}})$ & $(0,-\sqrt{\frac{2}{3}})$

(b) Length of major axis $=2a=2\times 1$

length of minor axis $=2b=2\times \sqrt{\frac{2}{3}}=2\cdot \sqrt{\frac{2}{3}}$

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2 years ago