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Lina20 [59]
3 years ago
7

What is the area of a regular hexagon with a radius of 14 inches

Mathematics
1 answer:
abruzzese [7]3 years ago
3 0
The area of the hexagon is 678.96
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Given the system of equations, what is the solution? 5x - 4y = 7 x = 5 - 3/2 y
xenn [34]
The answer is A


You can solve this by equation the two equations, by substitution method or elimination. Let's choose the substitution since Equation 2 has already X isolated
-take the X in equation 2 and substitute in the first equation
So, You should have 5 (5-3/2 y) -4y =7
Get y ( I'll assume you know how to simplify and find y by yourself )
y=36/23
-Now take y and substitute it in the first equation or the second equation (it doesn't really matter)
Substituting y in Equation 2:
x=5- 3/2 (36/23)
=> x= 61/23

So answer is A where (x,y) is (61/23, 36/23)
8 0
3 years ago
Read 2 more answers
Explain please and tell me how to do it ?
SCORPION-xisa [38]

The trick to calculating the area here is to subdivide the diagram into smaller parts. For example, there's a 3 cm-by-3cm square. The rectangle is 4 cm by 8 cm.. The triangle has a base of 5 cm and a height of 3 cm.

Total area = area of square + area of rectangle + area of triangle

= 9 cm^2 + 32 cm^2 + (1/2)(5 cm)(3 cm)

= (9 + 32 + 7.5) cm^2

= 48.5 cm^2 (total area of figure)

8 0
3 years ago
Read 2 more answers
List the given numbers from least to greatest -5, 3.14, 1/4, -3/2, 49
seraphim [82]
-3/2,-5,1/4,3.14,49 hope that helped!
8 0
3 years ago
Find the zeros of the polynomial function and state the multiplicity of each.
Oksi-84 [34.3K]

Answer:

a) 8, multiplicity 2; 8, multiplicity 3

Step-by-step explanation:

Remember that a is a zero of the polynomial f(x) if f(a)=0 and has multiplicity n if the termn (x-a) is n times in the factorization of f(x).

We have that

f(x)=3(x + 8)^2(x - 8)^3

Observe that

1. f(-8)=3(-8 + 8)^2(-8 - 8)^3=3*0*(-16)^3=0

and (x+8) appear two times in the factorization of f(x). Then -8 is a zero of f(x) with multiplicity 2.

2. f(8)=3(8 + 8)^2(8 - 8)^3=3*16^2*0^3=0

and and (x - 8) appear three times in the factorization of f(x). Then 8 is a zero of f(x) with multiplicity 3.

Since f(x) has degree 5 and the sum of the multiplicities is 5 then f(x) hasn't more zeros.

7 0
3 years ago
PLEASE HELP ME PLEASE HELP ME PLEASE ITS URGENT ANS PLS A GOOD ANSWER AND I DONT KNOW IF THE ONE I PICKED IS RIGHT
Ede4ka [16]

Answer:

The one you picked is right! Good job!

7 0
3 years ago
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