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drek231 [11]
2 years ago
14

How many pairwise comparisons must you make for a case with 15 statistically independent scenarios?

Mathematics
1 answer:
Levart [38]2 years ago
3 0

There are 105 comparisons made with 15 statistically independent scenarios.

According to the statement

we have given value of n is 15.

Then r = 2. so,

we use the formula NcR then

Substitute the values in it then

15c2

we open it according to ncr formula

In this formula we arrange the terms according to the following

NcR formula = n! /r! * (n-r)!

then the terms will arrange in this way.

So,

ncr = 15! / 2! * 13!

After solving the statement some terms will be cancel with each other and remaining terms are

ncr = 15*14/2

ncr = 210/2

ncr = 105

here the value becomes 105.

So, There are 105 comparisons made with 15 statistically independent scenarios.

Learn more about COMBINATION here brainly.com/question/12725706

#SPJ4

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Is (2, 5) a solution to this system of equations?<br> 6x + y = 17<br> 3x + 14y = 16<br> yes or no
Anarel [89]

Answer:

Putting the value of x= 2 in the first equation,

6(2)+y= 17

y= 17-12 = 5

This value is same as the value for y given in the question.

Therefore, it satisfies the equation.

Again, putting the value of x= 2 in the second equation,

3(2)+14y= 16

14y= 16-6 = 10

y= 10/14 = 5/7

It doesn't satisfies the 2nd equation

Hence, (2,5) is not the solution to this system.

5 0
3 years ago
A paper company needs to ship paper to a large printing business. The a paper will be
eimsori [14]

Given :

A paper company needs to ship paper to a large printing business.

The paper will be shipped in small boxes and large boxes.

Each small box of paper weighs 50 pounds and each large box of paper weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Find :

Determine the number of small boxes shipped and the number of large boxes shipped.

Calculations :

Let "S" be small boxes and "L" be large boxes.

Small box + Large box = 19

50S + 80L = 1280

→ 5S + 8L = 128

→ 5 (19 - L) + 8L = 128

→ 3L = 128 - 95

→ L = 33/3

→ L = 11ㅤㅤ

Finding the small box:

→ S = 19 - L

→ S = 19 - 11

→ S = 8

Therefore ,

Large boxes = 11.

Small boxes = 8.

orrrrrr

The number of small boxes is 8 and that of the large boxes is 11.

Step-by-step explanation:

Each small box of paper weighs 50 pounds and each large box of paper

weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Let there are x small boxes and y large boxes.

Then,

x + y = 19 ............ (1) and

50x + 80y = 1280

⇒ 5x + 8y = 128 ............... (2)

Now, solving equations (1) and (2) we get,

5( 19 - y) + 8y = 128

⇒ 3y = 128 - 95 = 33

⇒ y = 11

Now, from equation (1) we get, x = 19 - y = 19 - 11 = 8

Therefore, the number of small boxes is 8 and that of the large boxes is 11. (Answer)

8 0
3 years ago
Solve triangle ABC if a=10, b= 11, c=17
Svet_ta [14]

Answer:

38

Step-by-step explanation:

it is quite simple so try to solve it

3 0
2 years ago
Sam bought a soft drink for 4 dollars and 7 candy bars . he spent a total of 18 dollars. how much did each candy bar cost?
Masteriza [31]
18 dollars - 4 dollars for the drink = 14 dollars after you take out the drink
$14 divided by 7 candy bars = $2 per candy bar

8 0
3 years ago
A survey was given to 339 people asking whether people like dogs and/or cats.
liubo4ka [24]

Answer:

80.

Step-by-step explanation:

Let C be the set of people who like cats and D the set of people who like dogs. Under the cardinality theorem you have

n(CUD) = n(C) + n(D) - n(CnD)[/tex], isolating the (C∩(D , you have n(C∩(D  = n(C) + n(D) - (C∪.As a total of 339 individuals, and 88 are those who do not like cats or dogs, then 251 of them are those who like cats or dogs. Then, n[tex](C∩(D  = 190 +141 -251 = 80

6 0
3 years ago
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