Question

How would you describe the relationship between the real zeros and x-intercepts of the function y = log (x-2)?

Answer 1

Answer:

D. When you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3.

This is correct on ed-genuity, hope this helps :)

Answer 2

Answer:

When you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3.

Step-by-step explanation:

The given function is $y=\log (x - 2)$.

So, for real zeros and x-intercept, the y-coordinate must be equal to zero.

Then it becomes $0 = \log (x-2)$

⇒ x - 2 = 1 {Since log 1 = 0}

⇒ x = 3

Therefore, when you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3. (Answer)