What is the estimate of 242-220
2 answers:
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Answer:
The amount invested at 10% rate is $ 2200
Step-by-step explanation:
Given as :
The total amount earn by student = $6500
The total interest received at the end of year = $607
Let the amount invested at 10% rate = $x
So, The amount invested at 9% rate = ($6500 - $x)
Let the time for which money invested = 1 year
<u>Now from Simple Interest method :</u>
SI =
Or, SI_1 + SI_2 = +
Or, SI_1 + SI_2 =
Or, $607 × 100 = 10x + (6500-x) × 9
Or, $60700 = 10x- 9x + 58500
Or, $60700 - $58500 = x
Or , 2200 = x
∴ x = 2200
So, The amount invested at 10% rate = $x = $ 2200
Hence The amount invested at 10% rate is $ 2200 Answer
Answer:
C) 515 hours.
D) 500 hours
c) sample 3
Step-by-step explanation:
1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours
Sample Service Life (hours)
1 2 3
495 525 470
500 515 480
505 505 460
<u>500 515 470 </u>
<u>∑2000 2060 1880</u>
x1`= ∑x1/n1= 2000/4= 500 hours
x2`= ∑x2/n2= 2060/4= 515 hours
x3`= ∑x3/n3= 1880/4= 470 hours
2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using μ ± σ , μ±2 σ or μ ± 3 σ.
In this question the limits are determined by using μ ± σ .
3. Upper control limit = UCL = 520 hours
Lower Control Limit= LCL = 480 Hours
Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours
Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours
Sample 3 mean = x3`= ∑x3/n3= 1880/4= 470 hours
This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.
We see that the sample 3 mean is lower than the LCL. The other two means are within the given UCL and LCL.
This can be shown by the diagram.
