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3 years ago

In how many ways can the letters of the word CARPET be arranged

Mathematics

2 answers:

expeople1 [14]3 years ago

8 0

Answer: In so many ways ;

acre
cape
care
carp
cart
cate
pace
pact
pare
part
pate
pear
peat
pert
prat
race
at
rapt
rate
reap
race
tape
tare
tarp
tear
tepa

trap

ace
act
ape
apt
arc
are
art
ate
cap
car
cat
cep
ear
eat
era
pack
par
pat
pea
pec
per
pet
rap
rat
rec
rep
ret
tap
tar
tea

And so on .

Karo-lina-s [1.5K]3 years ago

4 0

<h2>Answer:</h2>

720

<h2>Explanation: </h2>

you would be using permutation i believe

because carpet has 6 letters you have six placement options

_x_x_x_x_x_

if you can only use the letters once

you can put all letters in p1

so 6x_x_x_x_x_

but because of that you would only be able to put all but one in p2 and one less than p2 in p3 going all the way to 1 in the last

so 6x5x4x3x2x1

i might be wrong but this has worked for me

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Step-by-step explanation:

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Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad

Deffense [45]

Answer:

a) $17-2.26\frac{1.9}{\sqrt{10}}=15.64$

$17+2.26\frac{1.9}{\sqrt{10}}=18.36$

So on this case the 95% confidence interval would be given by (15.64;18.36)

b) 1. n=15, conf =95% $\bar X= 35$ s=2.7

> round(qt(p=1-0.025,df=15-1),2)

[1] 2.14

> round(qt(p=0.025,df=15-1),2)

[1] -2.14

2. n=37, conf =99% $\bar X= 82$ s=5.9

> round(qt(p=1-0.005,df=37-1),2)

[1] 2.72

> round(qt(p=0.005,df=37-1),2)

[1] -2.72

3. n=1009, conf =90% $\bar X= 0.9$ s=0.04

> round(qt(p=1-0.05,df=1009-1),2)

[1] 1.65

> round(qt(p=0.05,df=1009-1),2)

[1] -1.65

Step-by-step explanation:

Part a: What is the lower bound to this confidence interval? 2 cm (round to 2 decimal places) What is the upper bound to this confidence interval? cm (round to 2 decimal places)

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

We have the following data:

$\bar x= 17$ represent the sample mean

$s = 1.9$ represent the sample deviation

n =10 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.26$