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2 years ago

On a fith grade benchmark exam with 55 questions total sunny answerd 80 % of them how many questions did he answer correctly

Mathematics

1 answer:

e-lub [12.9K]2 years ago

5 0

Answer:

44 answers

Step-by-step explanation:

80% of total questions are answered, ie 80% of 55 questions are answered.

So, (80/100) x 55 , ie 44 questions are answered.

Assuming that all answered questions are correct, 44 answers are correct.

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HELP PLEASE ASAP!!!!

Akimi4 [234]

Answer:

85°

Step-by-step explanation:

add 125+150=275

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2 years ago

Evaluate the expression Show your work b) -10 -5h for h = -6

vazorg [7]

Answer:

Step-by-step explanation:

-10-5x(-6)

-10+30

4 0

3 years ago

I need these three solved. I have a lot of math to do. the directions say solve each system of equations using substitution. sho

alekssr [168]

Answer:

x + 2(x + 1) = 8 --> x = 2

y = 2 + 1 = 3

3(9 + 2y) + 5y = 20 --> y = -7/11

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3 years ago

Solve x/10 = -7 a.x=-70 b.x=-0.7 c.x=3 d.x=-17

Brums [2.3K]

The answer is A. x=-70.

8 0

3 years ago

Right triangle FHG is shown. The sine of angle F is 0.53. What is the cosine of Angle h ?

g100num [7]

Given:

Given that FGH is a right triangle. The sine of angle F is 0.53.

We need to determine the cosine of angle H.

Cosine of angle H:

Given that the sine of angle F is 0.53

This can be written as,

$sin F=0.53$

Applying the trigonometric ratio, we have;

$\frac{HG}{FH}=0.53$ ----- (1)

Now, we shall determine the value of cosine of angle H.

Let us apply the trigonometric ratio $cos \ \theta=\frac{adj}{hyp}$ , we get;

$cos \ H=\frac{HG}{FH}$ ----- (2)

Substituting the value from equation (1) in equation (2), we get;

$cos \ H=0.53$

Thus, the cosine of angle H is 0.53

6 0

3 years ago