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3 years ago

Two brothers each purchase a new pair of hiking boots and two canteens. The hiking

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

6 0

Answer: 2(34) + 2c = 98

Step-by-step explanation:

C = cost of one canteen

2 pair of boots at $ 34 each plus 2 canteens at (c) each totals $98.

2(34) + 2c = 98

68 +2c = 98. Subtract 68 from both sides. 68 - 68 +2c = 98 -68

2c = 30. Divide both sides by 2.

2c/2 = 30/2

c = 15 so each canteen costs $15

Check: 2 ($34) + 2 ($15) = $98

$68 + $30 = $98

$98 = $98

2C = 98

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Consider the parabola r(t)equalsleft angle at squared plus 1 comma t right angle, for minusinfinityless thantless thaninfinity

kodGreya [7K]

Given:- $r(t)=< at^2+1,t>$ ; $-\infty < t< \infty$ , where a is any positive real number.

Consider the helix parabolic equation :

$r(t)=< at^2+1,t>$

now, take the derivatives we get;

$r{}'(t)=$

As, we know that two vectors are orthogonal if their dot product is zero.

Here, $r(t) and r{}'(t)$ are orthogonal i.e, $r\cdot r{}'=0$

Therefore, we have ,

$< at^2+1,t>\cdot < 2at,1>=0$

$< at^2+1,t>\cdot < 2at,1>=$

$=2a^2t^3+2at+t$

$2a^2t^3+2at+t=0$

take t common in above equation we get,

$t\cdot \left (2a^2t^2+2a+1\right )=0$

⇒ $t=0$ or $2a^2t^2+2a+1=0$

To find the solution for t;

take $2a^2t^2+2a+1=0$

The number $D = b^2 -4ac$ determined from the coefficients of the equation $ax^2 + bx + c = 0.$

The determinant $D=0-4(2a^2)(2a+1)$ $=-8a^2\cdot(2a+1)$

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola $r(t)=< at^2+1,t>$ i.e <1,0>

6 0

3 years ago

A new lawn has a perimeter of 278ft. And a width of 64ft. A bag of grass seed will cover 384ft of ground. How many bags of grass

Anit [1.1K]

Answer:

13 bags

Step-by-step explanation:

Area of the lawn: A=lw

w= 64 ft

P= 2(l+w)= 278 ft ⇒

l= 278/2- 64= 75 ft

A= 64*75= 4800 ft²

bags of seed required:

4800/384= 12.5 so 13 full bags needed

7 0

3 years ago

Find two numbers between 3.456 and 3.457

kow [346]

Answer:

3.4567

3.4568

Step-by-step explanation:

We need to find a number between 3.456 and 3.457. In order to do so, we need to dive deeper into the decimal to get numbers in-between.

We need to dive to the ten-thousandths place to get numbers between the two.

6 0

3 years ago

Write 800 as the product of its prime factors.

Alex_Xolod [135]

800|2
800|2
400|2
200|2
100|2
50|2
25|5
5|5
1

$800=2^5\cdot5^2$

8 0

3 years ago

Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract

anyanavicka [17]

Answer:

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8$

Step-by-step explanation:

The sum you are trying to understand is this.

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}$

Remember that in general when you have a geometric series

$\sum\limits_{n = 0}^{\infty} a*r^n$ you have that

$\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}$ and that equality is true as long as $|r| < 1$ .

Therefore here we have

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n$ and $\big|\frac{-1}{15} \big| = \frac{1}{15} < 1$

Therefore we can use the formula and

$\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n = \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16 = 15/8$

5 0

2 years ago