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Darina [25.2K]
3 years ago
5

For the function f(x)=x2-4, fins the value of f(x) when x=6

Mathematics
2 answers:
garri49 [273]3 years ago
7 0

f(x)=x^2-4\\f(6)=6^2-4\\f(6)=32

OR

f(x)=x*2-4\\f(6)=6*2-4\\f(6)=8

P.S. Hello from Russia

yuradex [85]3 years ago
3 0

Answer:

8

Step-by-step explanation:

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A woman has read manga 20 times in 20 days? how many minutes would that be?
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28800 minutes

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1 day = 24 hours

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Roys checking account pays 1% interest monthly and has a $10 service fee. if roys balance last month was $2223, find the amount
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3/4(2x-6)-2(1/2x+1)-1+5x
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Answer:

Distribute:

=(

3

4

)(2x)+(

3

4

)(−6)+(−2)(

1

2

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=

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2

x+

−9

2

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Combine Like Terms:

=

3

2

x+

−9

2

+−x+−2+−1+5x

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Suppose that when a transistor of a certain type is subjected to an accelerated life test, the lifetime x (in weeks) has a gamma
elena-14-01-66 [18.8K]

Answer:

a) P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

b) P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

Step-by-step explanation:

Previous concepts

The Gamma distribution "is a continuous, positive-only, unimodal distribution that encodes the time required for \alpha events to occur in a Poisson process with mean arrival time of \beta"

Solution to the problem

Let X the random variable that represent the lifetime for transistors

For this case we have the mean and the variance given. And we have defined the mean and variance like this:

\mu = 40 = \alpha \beta  (1)

\sigma^2 =320= \alpha \beta^2  (2)

From this we can solve \alpha and [/tex]\beta[/tex]

From the condition (1) we can solve for \alpha and we got:

\alpha= \frac{40}{\beta}    (3)

And if we replace condition (3) into (2) we got:

320= \frac{40}{\beta} \beta^2 = 40 \beta

And solving for \beta = 8

And now we can use condition (3) to find \alpha

\alpha=\frac{40}{8}=5

So then we have the parameters for the Gamma distribution. On this case X \sim Gamma (\alpha= 5, \beta=8)

Part a

For this case we want this probability:

P(1 \leq X \leq 40)

In order to find this probability we can use excel with the following code:

=GAMMA.DIST(40;5,8,TRUE)-GAMMA.DIST(1,5,8,TRUE)

And we got:

P(1 \leq X \leq 40)=0.560

Part b

For this case we want this probability:

P(X \geq 40)=1-P(X

In order to find this probability we can use excel with the following code:

=1-GAMMA.DIST(40,5,8,TRUE)

And we got:

P(X \geq 40)=1-P(X

6 0
3 years ago
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