3 years ago

For the function f(x)=x2-4, fins the value of f(x) when x=6

Mathematics

2 answers:

garri49 [273]3 years ago

7 0

$f(x)=x^2-4\\f(6)=6^2-4\\f(6)=32$

$f(x)=x*2-4\\f(6)=6*2-4\\f(6)=8$

P.S. Hello from Russia

yuradex [85]3 years ago

3 0

Answer:

Step-by-step explanation:

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Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.

torisob [31]

Fermat's little theorem states that
$a^p$ ≡a mod p

If we divide both sides by a, then
$a^{p-1}$ ≡1 mod p
=>
$a^{17-1}$ ≡1 mod 17
$a^{16}$ ≡1 mod 17

Rewrite
$a^{1000000}$ mod 17 as
$=(a^{16})^{62500}$ mod 17
and apply Fermat's little theorem
$=(1)^{62500}$ mod 17
=>
$=(1)$ mod 17

So we conclude that
$a^{1000000}$ ≡1 mod 17

6 0

4 years ago

Locate the points of discontinuity in the piecewise function shown below.

algol13

Answer:

Step-by-step explanation:

The given piecewise function i

From the given function it is clear that function is divided at x=-1 and x=2. It means we check the discontinuity at x=-1 and x=2.

For x=-1,

LHL:

Since LHL ≠ f(-1), therefore the given function is discontinuous at x=-1.

For x=2,