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2 years ago

For the function f(x)=x2-4, fins the value of f(x) when x=6

Mathematics

2 answers:

garri49 [273]2 years ago

7 0

$f(x)=x^2-4\\f(6)=6^2-4\\f(6)=32$

$f(x)=x*2-4\\f(6)=6*2-4\\f(6)=8$

P.S. Hello from Russia

yuradex [85]2 years ago

3 0

Answer:

Step-by-step explanation:

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KengaRu [80]

B is the answer.....

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3 years ago

Please show work for both problems

kirill [66]

Answer:

3) x = 15; 95 and 85 4) x = 12; 98 for both angles

Step-by-step explanation:

2x + 65 + 3x + 40 = 180 Set the equations equal to 180

5x + 105 = 180 Combine like terms

- 105 - 105 Subtract 105 from both sides

5x = 75 Divide both sides by 5

x = 15

Plug 15 into both equations

2(15) + 65 = 95

3(15) + 40 = 85

4) 5x + 38 = 9x - 10 Set the equations equal to each other

- 5x - 5x Subtract 5x from both sides

38 = 4x - 10

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Plug 12 into both equations

5(12) + 38 = 98

9(12) - 10 = 98

6 0

2 years ago

If (42)^p = 41^4, what is the value of p?

babymother [125]

First you need to make both bases the same:

Lets remove the ^p and ^4

To make the base of 42 equal to 41, you would have 41^x = 41

X - ln(42) / ln(41) = 1.00648904

Now you have 41^1.00648904(p) = 41^4

Now the bases are equal so we need to set the exponents to equal:

1.00648904(p) = 4

Divide both sides by 1.00648904 to solve for P

P = 4 / 1.00648904

P = 3.97421114

4 0

3 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

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2 years ago

Whoever gets this correct gets a brainliest .

Alisiya [41]

Answer:

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Step-by-step explanation:

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3 0

3 years ago