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pantera1 [17]
2 years ago
6

Please answer this correctly without making mistakes

Mathematics
1 answer:
serious [3.7K]2 years ago
6 0

Answer:

554/5,948

Step-by-step explanation:

burgers with pickles: 554

burgers without pickles: 5,394

total burgers = 554 + 5,394 = 5,948

ratio of numbers of burgers with pickles to total burgers: 554/5,948

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Which of the following sample types should you always regard as unreliable? A) voluntary response samples 18) 9 simple random sa
Inessa [10]

Answer:

The type of sample that can be considered unreliable is type (a), in which responses are voluntary.

Step-by-step explanation:

The type of sample that can be considered unreliable is type (a), in which responses are voluntary.

It can be considered unreliable because being voluntary, the answers will give a biased result and the analysis will not be valid.

The rest of the options, if the necessary collections are taken, are samples that can be considered reliable.

4 0
3 years ago
5x+10=5(x+2) what is the answer I’ll give u 85 points
asambeis [7]

Answer:

All real numbers of x.

Step-by-step explanation:

5x+10=5(x+2) have the exact same equations on both sides.

5x+10=5x+10

If both are graphed, they will intersect each other for every value of x.

5 0
2 years ago
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Select the equation that is equivalent to the equation: y-3=2(x+5).
jeyben [28]
Y - 3 = 2(x+5)
y - 3 = 2x + 10
-3 - 10 = 2x - y
-13 = 2x - y

D) 2x - y = -13
6 0
2 years ago
I need help very quickly, please!!​
cestrela7 [59]

Answer:

32ft

Step-by-step explanation:

Tan = opp/adj

Tan(65) = n / 15

Tan(65) x 15 = n

n = 32.16 = 32ft

5 0
2 years ago
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He two-way table shows the medal count for the top-performing countries in the 2012 Summer Olympics.
igomit [66]

Answer:

The 1st statement i.e. "The probability that a randomly selected silver medal was awarded to Great Britain is StartFraction 17 Over 99 EndFraction" is true.

Step-by-step explanation:

<em>The</em><em> </em><em> table:</em>

                         Gold        Silver           Bronze       Total

United States    46          29                29               104

China                  38          27                23                 88

Russia                 24          26                32                 82

Great Britain       29           17                19                 65

Total                    137          99               103              339

Let S be the sample space and E be the event and P(E) by the probability of a certain event.

1st Statement: The probability that a randomly selected silver medal was awarded to Great Britain is StartFraction 17 Over 99 EndFraction.

As the total number of silver medals are = n(S) = 99

The number of silver medals won by Great Britain = n(E) = 17

P(E) = n(E)/n(S) = 17/99

Hence, the probability that a randomly selected silver medal was awarded to Great Britain is 17/99.

So, the 1st statement i.e. "The probability that a randomly selected silver medal was awarded to Great Britain is StartFraction 17 Over 99 EndFraction" is true.

2nd Statement: The probability that a randomly selected medal won by Russia was a bronze medal is StartFraction 32 Over 103 EndFraction.

As the total number of medals won by Russian are = 82 = n(S) = 82

The number of bronze medals won by Russia are = n(E) = 32

P(E) = n(E)/n(S) = 32/82 = 16/41

Hence, the probability that a randomly selected medal won by Russia was a bronze medal is 16/41.

So, the 2nd statement i.e. "The probability that a randomly selected medal won by Russia was a bronze medal is StartFraction 32 Over 103 EndFraction" is NOT true.

3rd Statement: The probability that a randomly selected gold medal was awarded to China is StartFraction 88 Over 137 EndFraction.

As the total number of gold medals are = n(S) = 137

The number of gold medals won by China are = n(E) = 38

P(E) = n(E)/n(S) = 38/137

Hence, the probability that a randomly selected gold medal was awarded to China is 38/137.

So, the 3rd statement i.e. "The probability that a randomly selected gold medal was awarded to China is StartFraction 88 Over 137 EndFraction" is NOT true.

4th Statement: The probability that a randomly selected medal won by the United States was a silver medal is StartFraction 104 Over 339 EndFraction.

As the total number of medals won by United States are = n(S) = 104

The number of silver medals won by United States are = n(E) = 29

P(E) = n(E)/n(S) = 29/104 = 29/104

Hence, The probability that a randomly selected medal won by the United States was a silver medal is 29/104.

So, the 4th statement i.e. "The probability that a randomly selected medal won by the United States was a silver medal is StartFraction 104 Over 339 EndFraction." is NOT true.

Keywords: Probability, event

Learn more about probability from brainly.com/question/13604758

#learnwithBrainly

5 0
3 years ago
Read 2 more answers
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