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Elenna [48]
3 years ago
13

EMERGENCY!!!!! PLEASE HELP

Mathematics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

y = 1/8 x^2 - 5/4 x + 49/8.

Step-by-step explanation:

The vertex is always halfway between the directrix and the focus and the parabola always curves away from the directrix so the equation  will be of the form y = ax^2 + bx + c . It opens upwards. The absolute value of  p will be the distance from the vertex to the focus and the distance between the vertex and the focus. So

|p| = 3-1 = 2.  It is positive because the parabola opens upwards. The focus will be at  (5, 3+2) = (5, 5).

Using the formula:  

4p(y - k) = (x - h)^2    where  (h, k) is the vertex, we have:

8(y - 3) = (x - 5)^2

Converting this to general form:

8y - 24 = x^2 - 10x + 25

8y = x^2 - 10x + 49

y = 1/8 x^2 - 5/4 x + 49/8

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Calculate axis of symmetry and vertex for equation 4x squared + 8x = 32
Sloan [31]

Answer:

x=2,−4 hope this was help full

6 0
3 years ago
The amount of chlorine in a swimming pool varies directly with the volume of water. the pool has 2.5 milligrams of chlorine per
djverab [1.8K]

Answer:

Find out the  how much chlorine is in the pool .

To prove

As given

The amount of chlorine in a swimming pool varies directly with the volume of water.

The pool has 2.5 milligrams of chlorine per liter of water.

i.e

2.5 milligrams of chorine = 1 litre of water

There are 8000 gallons of water in the swimming pool.

As 1 gallons = 3.78541 litre (Approx)

Now convert 8000 gallons of water in litres.

8000 gallons = 8000 × 3.78541 litre

                      = 30283.28 litres

Now calculate chlorine in the pool for 30283.28 litres  of waters.

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2.5 milligrams of chlorine = 1 litre of water

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3 0
3 years ago
Read 2 more answers
Find y (please someone answer)
Alex73 [517]

Answer:

Y=√2

Step-by-step explanation:

We can use the pathagorian theorum: A²+B²=C² now in this case it would be X²+Y²=2² we also know that  X and Y are the same number in this problem because they have the same corresponding angle (triangle angles always add to 180 and since we know 2 of the angles are 45 and 90 the remaining angle will also be 45) Because of this we can change our equation to Z²+Z²=2² (I'm using Z so that we do not confuse it with another letter we've already used) from there we can go to Z∧4=2² and then we will solve the equation. Z=√2 Z also equals X and Y therefore Y=√2

I hope this helps and please let me know if there is anything you don't understand I would be happy to clarify!

5 0
3 years ago
Write an expression for the calculation the difference of the products of 5 and 2 and 5 and 1
oee [108]
Let's review the terminology.  A product is what you get when you multiply two numbers.  So, the product of 5 and 2 is basically "5*2," and the product of 5 and 1 is "5*1."

The difference means when you subtract one from the other.  So, the difference of 5*2 and 5*1 means "(5*2)-(5*1)".  (Note: I put in parentheses to make sure the reader understands that 5*2 is separate from 5*1.  5*2-5*1 is confusing: you might not know what to do first!)

So, "(5*2)-(5*1)" can be your answer, OR you can simplify it further by actually doing the multiplication: "10-5".  If you want the answer, just subtract--the expression is equal to 5.

Answer: "<span>(5*2)-(5*1)" OR "10-5" OR "5"</span>
3 0
4 years ago
PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS
Elina [12.6K]

You want to end up with A\sin(\omega t+\phi). Expand this using the angle sum identity for sine:

A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi

We want this to line up with 2\sin(4\pi t)+5\cos(4\pi t). Right away, we know \omega=4\pi.

We also need to have

\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}

Recall that \sin^2x+\cos^2x=1 for all x; this means

(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}

Then

\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)

So we end up with

2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)

8 0
3 years ago
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