All categories

3 years ago

What is the first step in simplifying the expression

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

11x-2-3(1-7x)^2/(1x+1)

11x-2-3-21x/1+1

-32x-2-3-1

-32x-1+1

-32=0

/-32 /-32

x=0

Mama L [17]3 years ago

6 0

For this case we have the following expression:

$\frac {11x-2-3 (1-7x) ^ 2} {(x + 1)}$

We must indicate the first step that allows to start the simplification of the expression.

It is observed that the first step to follow is to solve the square of the binomial that is in the numerator of the expression.

$(1-7x) ^ 2$

Answer:

Option A

You might be interested in

If the area of a right triangle is 9/16 sq. ft. and the height is 3/4 ft, write an equation that relates the area to the base,b,

Rudik [331]

Answer:

Base = 1.5 ft

Step-by-step explanation:

Area = ½ × base × height

9/16 = ½ × base × 3/4

9/16 = 3/8 × base

base = 9/16 × 8/3

base = 3/2

base = 1½ ft

5 0

3 years ago

What is the value of x in the equation

seraphim [82]

1/3 x - 1/2 = 18 1/2
1/3 x = 19 (add 1/2 on the right side to 18 1/2)
x = 57 (multiply the reciprocal of 1/3 and that will be 3/1 or 3 to 19 to get x by itself)
So, the answer is x = 57 (d. 57)

6 0

4 years ago

An equivalent expression for 12x+1 and 2(2x+5) please help

zhannawk [14.2K]

<h2>Answer:</h2>

8x+9

<h2>Step-by-step explanation:</h2>

12x+1 = 2(2x+5)

<h3><em><u>Handle the brackets first</u></em></h3>

12x+1 = 4x+10

<h3><em><u>Collect like terms</u></em></h3>

=8x+9

3 0

3 years ago

Which values of x make this equation true?

Evgesh-ka [11]

Answer:

${x}^{2} + x = 12 \\ {x}^{2} + x - 12 = 0 \\ {x }^{2} + 4x - 3x - 12 = 0 \\ x(x + 4) - 3(x + 4) = 0 \\ (x + 4)(x - 3) = 0 \\ either \: \: \: or \: \\ x = - 4 \: \: \: \: \: \: \: \: \: \: \: \: x = 3$

the answer is -4 and 3

3 0

2 years ago

Show that if the first 10 positive integers 1,2,3,···,10 are placed around a circle, in any order,there exists three integers in

zysi [14]

Answer:

Let A1=a1+a2+a3, A2=a2+a3+a4, and so on, A10=a10+a1+a2. Then A1+A2+⋯+A10=3(a1+a2+⋯+a10)=(3)(55)=165, so some Ai≥165/10=16.5, so some Ai≥17.

Step-by-step explanation:

7 0

3 years ago