Answer:
The average force applied to the baseball is 8.25kN
Step-by-step explanation:
This problem bothers on the impulse of a force
We know that the change in momentum is expressed as
Ft= mv-mu
Given
Ft=16.5 kg-ms
Time t of impact =0.00200s
The force applied can be solved for
By making F subject of formula
F= (mv-mu)/t
F=16.5/0.002
F= 8250N
F= 8.25kN
<h2>
Explanation:</h2>
Here we have the following expression:
So we need to extend this. Remember that the difference of squares tells us:
So here:
Thus:
I think you solved it on your own because x is 82
Y *x =20
y +x =9
rewrite 1st eq. as y = 20/x
subsituute that into 2nd eq.
20/x +x =9
multiply each term by X
20 +x^2 = 9x
subtract 9x from each side:
x^2 - 9x +20 = 0
now factor:
(x-5) (x-4) = 0
solve for x
5-5 = 0
4-4 = 0
so X can be 4 or 5
replace x into equations and solve for Y
so when X = 4, Y = 5
When X = 5, Y = 4
x= 5,4
y = 4,5
3125 !! If I was correct.
