2 years ago

PLEASEM HELP OMG HEELPPPPPPPPPPPP

1 answer:

muminat2 years ago

4 0

Answer: 0, 25, 18, and -2
Explanation: When you plug all these numbers into the equation for x, they come out to be greater than -3.

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If $W$ is a random variable representing your winnings from playing the game, then it has support

$W=\begin{cases}43&\text{if you draw something with value at most 3}\\-11&\text{otherwise}\end{cases}$

There are 52 cards in the deck. Only the 1s, 2s, and 3s fulfill the first condition, so there are 12 ways in which you can win $43. So $W$ has PMF

$P(W=w)=\begin{cases}\frac{12}{52}=\frac3{13}&\text{for }w=43\\1-\frac{12}{52}=\frac{10}{13}&\text{for }w=-11\\0&\text{otherwise}\end{cases}$

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$E[W]=\displaystyle\sum_ww\,P(W=w)=\frac{43\cdot3}{13}-\frac{11\cdot10}{13}=\boxed{\frac{19}{13}}$

or about $1.46 per game.

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