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4 years ago

10

The length of time for one individual to be erved at a cafeteria is a random variable having an ex- ponential distribution with

a mean of 4 minutes. What is the probability that a person will be served in less than/3 minutes on at least 4 of the next 6 days?

1 answer:

777dan777 [17]4 years ago

6 0

Answer:

less than 3

Step-by-step explanation:

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3m/2/3=7 pleasee helpp

snow_tiger [21]

Answer:

14

Step-by-step explanation:

3 times 14 equals 42, and 42 divided by 2 is 21. 21 divided by 3 is 7. :)

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3 years ago

Let's find the unknown variables in the following cases. ) (a) If C.P. Rs 150 and profit = Rs 12, find profit percent

vivado [14]

Answer:

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Step-by-step explanation:

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MA_775_DIABLO [31]

Hello,

If center is (0,0)

x²/a²+y²/b²=1 for a half horizontal axis of a, and a half vertical axis of b

Here

a=2 ==> a²=4

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3 years ago

Does 2/3 = 8/12 and would you have to times them both by 4 and 3 to get the answer?

Serjik [45]

Answer:

2/3 =8/12

Step-by-step explanation:

2/3

Multiply the top and bottom by 4 to get a denominator of 12

2/3 *4/4

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3 years ago

45 x 3.5 please explain

Alinara [238K]

Answer:

157.5

Step-by-step explanation:

Try like this:

45 times 3.5

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