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DiKsa [7]
3 years ago
6

15 < d divided by 400

Mathematics
1 answer:
makvit [3.9K]3 years ago
8 0
.0375 that is the answer your welcome
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Solve f(x)=x²+7x+12/-x²-3x+4
Zarrin [17]

x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{The domain:} x\neq-4\ and\ x\neq1\\\\canceled\ (x+4)\\\\f(x)=\dfrac{x+3}{-(x-1)}=-\dfrac{x+3}{x-1}\ for\ x\neq-4\ and\ x=1

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Naya [18.7K]
2. 11 2/16 that’s for answers number 2
3 0
3 years ago
Hey plz could you help me with this???? Tysm
miss Akunina [59]

Answer:

25.71

Step-by-step explanation:

πr + d

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6 0
3 years ago
What is the minimum value for g(x)=x2−10x 16? enter your answer in the box.
motikmotik

The minimum value for g(x)=x² - 10x + 16 is -9

<h3>How to determine the minimum value?</h3>

The function is given as:

g(x)=x² - 10x + 16

Differentiate the function

g'(x) = 2x - 10

Set the function 0

2x - 10 = 0

Add 10 to both sides

2x = 10

Divide by 2

x = 5

Substitute 5 for x in g(x)

g(5)=5² - 10*5 + 16

Evaluate

g(5) = -9

Hence, the minimum value for g(x)=x² - 10x + 16 is -9

Read more about quadratic functions at:

brainly.com/question/7784687

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3 years ago
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