If depreciation is 7.25% per year, then the common factor is (1-0.0725), or 0.9275.
Thus, the car's value after 5 years will be:
V = $28000(0.9275)^5 = $28000(0.6864) = $19218.86, or (to the nearest dollar) $19218 (answer)
Joanna bought 7 notebooks and 14 pencils
Step-by-step explanation:
Step 1 :
Let x denote the number of notebooks and y denote the number of pencils Joanna bought.
Cost of one notebook = $ 2.30
Cost of one pencil = $1.42
Step 2 :
Total of notebooks and pencils bought = 21
=> x + y = 21 => y = 21-x
Total cost of notebooks and pencils = $35.98
=> 2.3x + 1.42y = 35.98
Substituting y = 21- x here , we have,
2.3x + 1.42 ( 21-x) = 35.98
2.3x + 29.82 - 1.42x = 35.98
0.88 x = 6.16
=> x = 7
y = 21-x = 21-7 = 14
Step 3 :
Answer :
Joanna bought 7 notebooks and 14 pencils
Answer:
3
Step-by-step explanation:
Answer:
2.07
Step-by-step explanation:
