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BaLLatris [955]

2 years ago

7

Someone please answer this

1 answer:

babymother [125]2 years ago

4 0

Answer:

9.4m is the answer.

Step-by-step explanation:

a = 8m

b = 5m

c = ?

According to the Pythagoras theorem,

a² + b² = c²

8² + 5² = c²

64 + 25 = c²

89 = c²

c = 9.433

Rounding off,

c = 9.4m

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The length of a pole is to be 6.5ft. The actual length of the pole may vary by as much as 0.02ft. Write an absolute value inequa

Airida [17]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

|x - 6.5| < 0.02 ft is the <span>absolute value inequality for the possible lengths of the pole.</span>

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3 years ago

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german

Tan A = BC/AB = 15/8

answer is B. 15/8

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The area of a rectangle or a 48 square inches the length is 8 inches what is the measure of its width

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6 inches because area= length times width and 6 times 8= 48 inches

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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago

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MrRissso [65]

Answer:

2x^2 +11

Step-by-step explanation:

f(x) = 3x^2 +2

g(x) = x^2 -9

f(x) - g(x) = 3x^2 +2 - (x^2 -9)

Distribute the minus sign

= 3x^2 +2 -x^2 +9

Combine like terms

= 2x^2 +11

5 0

2 years ago

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