Remark
This is a very interesting question. Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.
y = x (1)
3x + 4y = 12 (2)
Put x in for y in equation 2
3x + 4x = 12
7x = 12
x = 12/7
x = 1.714
y = 1.714
Problem A
<em><u>x intercept</u></em>
The x intercept occurs when y = 0
3x + 4(0) = 12
3x = 12 Divide by 3
x = 12/3
x = 4
the x intercept = (4,0)
<em><u>y intercept</u></em>
The y intercept occurs when x =0
3(0) + 4y = 12
4y = 12
y = 12/4
y = 3
y intercept = (0,3)
Problem B
x and y both equal 1.714 so they are also the length of the square's side.
Problem C
See solution above. x =y is the key fact.
x = y = 1.714
Answer:
x= 5/2w-15 .
Step-by-step explanation:
See the image below:)
Answer:
The answer is A
Step-by-step explanation:
i just got it right
Question 1.). Solve:
2 (x - 1 / 2) = 3 (5 - 2x)
Simplify both sides of equation:
2( x - 1 / 2 ) = 3(5 - 2x )
(2) (x) + (2) ( -1 / 2 ) = (3) (5) + (3) ( -2x )
Distribute:
2x + - 1 = 15 + -6x
2x - 1 = -6x + 15
Add 6x to both sides:
2x - 1 + 6x = -6x + 15 + 6x
8x - 1 = 15
Add 1 to both sides:
8x - 1 + 1 = 15 + 1
8x = 16
Divide both sides by 8:
8x / 8 = 16 / 8
Answer: 2 (x - 1 / 2) = 3 (5 - 2x) ==========> x = 2
Question 2.).
M =======> Amount Malik need
Solution: =========> m ≥ 5
Inequality ========> 8 + 7 + 10 + m ≥ 30
25 + m ≥ 30
Interpretation ==========> Malik needs at least, $5 .00 to get to, $30.00 or more.
Is the solution reasonable ===========> YES
Hope that helps!!!!! : )
