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kkurt [141]
4 years ago
14

HELPPPP!. . You have checked out b books from the library, where b is a number greater than 5. You plan to read three of the boo

ks and return them at the end of this week. In how many ways can you pick the books you will read first, second, and third?. . the choices are . . A. b3 ways. . B. b3- 3b2 + 2b ways. . C. b3 - 9b2 + 27b - 27 ways. . D. 5b - 3 ways
Mathematics
2 answers:
Helga [31]4 years ago
3 0
The answer to your question is b to the 3 good luck
Nat2105 [25]4 years ago
3 0
"b3- 3b2 + 2b ways" is the one among the following choices given in the question that describes how many ways you can pick the books you will read first, second, and third. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer helped you.
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Write the equation of a line whose graph has the same slope as
Sveta_85 [38]

Answer:

y= 1/3x -3

Step-by-step explanation:

For the y-int for 8x-2y=6 is (0, -3).

For the slope of 3x-9y=9 is 1/3.

3 0
3 years ago
How do you solve 1/3x = 20 to find x
Alex
1/3x=20

1st step do the opposite of 1/3x to get it by itself. So you would do 1/3x *3/1 than you would do 3/1 *20. What you do to that side you do to the other.

2nd step 20*3=60

3rd You can check your answer by doing 1/3 *60=20

I plugged the answer in the variable to Check it
7 0
3 years ago
PLS HELP I DONT UNDERSTAND
suter [353]

Answer:

A

Step-by-step explanation:

4(0.5x+2.5y-0.7x-1.3y+4)

=2x+10y-2.8x-5.2y+16

=-0.8x+4.8y+16

hope this helps :)

6 0
3 years ago
I think number 9 is b or c, i don't know what 10 is. please help me!!!
scoray [572]
10 is letter b. I hope this helps!!!
7 0
4 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

f(x,y,z)=10x+10y+3z

g(x,y,z)=5x^2+5y^2+3z^2=43

We have to find the extreme values of the function.

f_x(x,y,z)=10,f_y(x,y,z)=10,f_z(x,y,z)=3

g_x(x,y,z)=10x,g_y(x,y,z)=10y,g_z(x,y,z)=6z

\Delta f(x,y,z)=\lambda \Delta g(x,y,z)

Therefore,

10=\lambda 10x\implies x=\frac{1}{\lambda}

10=10y\lambda\implies y=\frac{1}{\lambda}

3=6z\lambda

z=\frac{1}{2\lambda}

Substitute the values in g(x)

Then, we get

\frac{5}{\lambda^2}+\frac{5}{\lambda^2}+\frac{3}{4\lambda^2}=43

\frac{20+20+3}{4\lambda^2}=43

\frac{43}{4\lambda^2}=43

\lambda^2=\frac{43}{4\times 43}

\lambda=\pm\frac{1}{2}

When \lambda=\frac{1}{2} then,

x=2,y=2,z=1

When \lambda=-\frac{1}{2}

Then, x=-2,y=-2,z=-1

f(2,2,1)=10+10+3=23

f(-2,-2,-1)=-10-10-3=-23

Hence, maximum value of f(x,y,z) is 23 at (2,2,1) and minimum value of f(x,y,z) is -23 at (-2,-2 ,-1).

8 0
4 years ago
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