Find the greatest common factor

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

4 0

Answer:

$1$

Step-by-step explanation:

$7w^2$ and $9m^3$ does not have any common factor except for $1$

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Justin wanted to wrap his moms birthday present shaped like a rectangular prism with pretty paper. The box is 2.1 feet long, 2.7

JulijaS [17]

Answer:

42.06 ft²

Step-by-step explanation:

2 sides = 2(2.7 ft × 3.2 ft) = 2 × 8.64 ft² = 17.28 ft²

Front + back = 2(2.1 ft × 3.2 ft) = 2 × 6.72 ft² = 13.44 ft²

Top + bottom = 2(2.1 ft × 2.7 ft) = 2 × 5.67 ft² = <u>11.34 ft² </u>

Total area = 42.06 ft²

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Given the function f(x) square root x+1 -6choose the correct transformation.

Ahat [919]

Down 6
Left 1
I think hope it helps tho

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3 years ago

A farmer examines a sample of 25 cartons of eggs and finds that 3 contains cracked eggs. What is the best prediction of the numb

sertanlavr [38]

I believe it's C) 60 because ideally it would be 3 for every 25, 20 x 25 = 200, so then you would do 3 x 20 = 60

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3 years ago

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Can someone PLEASE help me with Trigonometry???

Svetach [21]

$\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}$

but anyway, the numerator will give the angles, and θ is just half of each

$\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025$

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there

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3 years ago

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qaws [65]

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3 years ago

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