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Leviafan [203]
3 years ago
8

Determine the volume of one rectangiular prism v(x)=54x^3+264x^2-738x+420 ?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0
We have 
<span>v(x)=54x^3+264x^2-738x+420 , and the sum of coefficients are
54+264-738+420=0, so 1 is a zero of v(x), it means v(1)=0
so v(x) can be written as v(x)= (x-1) Q(x)
and obviously, Q(x) = v(x) / (x-1)
</span>Q(x)=54x^3+264x^2-738x+420/(x-1)= (6x+42)(9x-10)
v(x)=(x-1)(6x+42)(9x-10)
<span>
the volume of rectangular prism is V= LxWxH
we can assume tha L=x-1, W=6x+42 and H= 9x-10

</span>
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Answer:

(C)

Step-by-step explanation:

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Area rectangle CDHG=  l{\times}b

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Area rectangle HGFE= l{\times}b

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Area of triangles CIH and DIG= 2{\times}\frac{1}{2}{\times}b{\times}h

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