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Ganezh [65]
3 years ago
6

A right triangle has one leg with a length of 48 and a hypotenuse with a length of 80. What is the length of the other leg?

Mathematics
1 answer:
victus00 [196]3 years ago
4 0
Using the pythagorean theorem (a^2 + b^2 = c^2), this would make the equation 48^2 + b^2 = 80^2 (the hypotenuse must be plugged in as the "c" value).

Once you solve, this becomes 2304 + b^2 = 6400.

Subtract 2304 from 6400 and you get b^2 = 4096.

Take the square root of 4096 and you get b=64.


The answer is 64.
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What is the next number in this pattern? 1,7,8,15,23,38,61
Kruka [31]

Answer:

72

Step-by-step explanation:

1 then 7+1=8 8+7=15 15+8=23 23+15=38 38+23=61

Ta Da I have taught you the pattern now you can show your work just in case you have one of those teachers hope this helped

8 0
3 years ago
Have a look of the drawing... What is "d" value? I have tried many methods but don't find how to solve... Pleaseeee
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I´d say "d" is the distance from the eye to the wall. 
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
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3 0
3 years ago
Read 2 more answers
1.4x10 -2 in standard form
sesenic [268]

Answer:

12

Step-by-step explanation:

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4 0
2 years ago
A local farm sells strawberries and blueberries. The ratio of the number of strawberries to blueberries it sells at 5:3. If it s
olganol [36]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
When Judy worked 4 hours and Ben worked 1 hour, their combined pay was $75. When Judy worked 2 hours and Ben worked 6 hours, the
arsen [322]

Answer:

$15

Step-by-step explanation:

let the hourly rate of pay for Ben  = B

let the hourly rate of pay for Judy  = J

Judy worked 4 hours and Ben worked 1 hour, their combined pay was $75;

              4J + B = 75 ----- i

Judy worked 2 hours and Ben worked 6 hours, their combined pay was $120

               2J + 6B  = 120 --- ii

Now, we should solve the expression;

   Multiply equation ii by 2 and equation i by 1;

 

            4J + B = 75 ----- i    x 1  ;    4J + B  = 75          -- iii

            2J + 6B  = 120 --- ii  x 2 ;   4J + 12B  = 240    ---iv

Now,

 equation iv - iii;

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So, solving for J;

          4J + B = 75

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          4J  = 75 - 15  = 60

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3 0
3 years ago
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