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3 years ago

A right triangle has one leg with a length of 48 and a hypotenuse with a length of 80. What is the length of the other leg?

1 answer:

4 0

Using the pythagorean theorem (a^2 + b^2 = c^2), this would make the equation 48^2 + b^2 = 80^2 (the hypotenuse must be plugged in as the "c" value).

Once you solve, this becomes 2304 + b^2 = 6400.

Subtract 2304 from 6400 and you get b^2 = 4096.

Take the square root of 4096 and you get b=64.

The answer is 64.

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Simplify V45 (square root 45) fully, giving your answer in the form aVb (square root)

inna [77]

Answer:

Step-by-step explanation:

7 0

3 years ago

Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )

DedPeter [7]

(a) First find the intersections of $y=e^{2x-x^2}$ and $y=2$ :

$2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}$

So the area of $R$ is given by

$\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx$

If you're not familiar with the error function $\mathrm{erf}(x)$ , then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line $y=1$ with $y=e^{2x-x^2}$ .

$1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2$

So the area of $S$ is given by

$\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx$
$\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx$

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve $y=e^{2x-x^2}$ and the line $y=1$ , or $e^{2x-x^2}-1$ . The area of any such circle is $\pi$ times the square of its radius. Since the curve intersects the axis of revolution at $x=0$ and $x=2$ , the volume would be given by

$\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx$

5 0

3 years ago

What is the value of x?

nalin [4]

Answer:

x = 42.9 m

Step-by-step explanation:

Corresponding sides of similar triangles MAB and MNP are proportional. This means ...

x/MP = MA/MN

However, we don't have a number for MA yet, so we need to find it.

MA +AN = MN

MA = MN - AN subtract AN

MA = 67.2 m - 32 m = 35.2 m

Now, we can use this to find x.

x = MP · (MA/MN) = (81.9 m) · 35.2/67.2

x = 42.9 m

4 0

3 years ago

PLS HELP. It’s question 18

Gnom [1K]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A clothes shop has some special offers.

castortr0y [4]

Answer:

The cost of 5 jumpers will be £ 58.40 (one more can be taken for free), the cost of 4 T shirts will be £ 9.60, and the total cost of the purchase will be £ 68.

Step-by-step explanation:

Since a clothes shop has some special offers, for which T-shirts are buy one get one free and jumpers are 3 for 2, and the normal price of a T-shirt is £ 4.80 and the normal price of a jumper is £ 14.60, to determine how much does it cost to get 5 jumpers and 4 T-shirts using this offer as appropriate, the following calculation must be performed:

4 T shirts = 2 + 2

4.80 x 2 = 9.60

5 jumpers = 2 (+1) + 2

4 x 14.60 = 58.40

Therefore, the cost of 5 jumpers will be £ 58.40 (one more can be taken for free), the cost of 4 T shirts will be £ 9.60, and the total cost of the purchase will be £ 68.

6 0

3 years ago