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2 years ago

A right triangle has one leg with a length of 48 and a hypotenuse with a length of 80. What is the length of the other leg?

1 answer:

4 0

Using the pythagorean theorem (a^2 + b^2 = c^2), this would make the equation 48^2 + b^2 = 80^2 (the hypotenuse must be plugged in as the "c" value).

Once you solve, this becomes 2304 + b^2 = 6400.

Subtract 2304 from 6400 and you get b^2 = 4096.

Take the square root of 4096 and you get b=64.

The answer is 64.

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155% of what number is 43.4?

Fed [463]

67.27

155 = 1.55 x 43.4 = 67.27

7 0

2 years ago

Read 2 more answers

A phone sells for $700. It is now on sale for 1/5 off the

Leona [35]

$\text{Find how much she was discounted:}\\\\\text{We know that the base price of the phone is 700}\\\\\text{It's on sale for 1/5 of the price (20\%), so multiply 700 by 0.20 and subtract}\\\\700*0.20=140\\\\700-140=560\\\\\text{Now, we know that there's a 10\% discount off the sale price, so precede}\\\text{with the same steps}\\\\560*0.10=56\\\\560-56=504\\\\\text{To find total discount price, subtract 504 from the original price}\\\\700-504=196\\\\\boxed{\$196}$

5 0

2 years ago

40. In a statistics class of 30 students, there were 13 men and 17 women. Two of the men and three of the women received an A in

Harrizon [31]

Answer:

a) 56.67% probability that the student is a woman

b) 16.67% probability that the student received an A

c) 63.33% probability that the student is a woman or received an A.

d) 83.33% probability that the student did not receive an A.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have that:

30 students

13 men

17 women

2 men that got an A and 11 men that did not get an A.

3 women that got an A and 14 women that did not get an A.

a. Find the probability that the student is a woman.

30 students, of which 17 are women.

$P = \frac{17}{30} = 0.5667$

56.67% probability that the student is a woman

b. Find the probability that the student received an A.

30 students, of which 5 received an A

$P = \frac{5}{30} = 0.1667$

16.67% probability that the student received an A

c. Find the probability that the student is a woman or received an A.

30 students, of which 17 are women and 2 are men who received an A. So

$P = \frac{19}{30} = 0.6333$

63.33% probability that the student is a woman or received an A.

d. Find the probability that the student did not receive an A.

30 students, of which 25 did not receive an A.

$P = \frac{25}{30} = 0.8333$

83.33% probability that the student did not receive an A.

7 0

2 years ago

A shelf has 20 bags of potatoes. Two of the bags have potatoes starting to go bad. The probability of drawing a bag with bad pot

nekit [7.7K]

Probability of drawing bad potatoes = 0.1

The probability of drawing a bag with bad potatoes is less than 1.

The probability of drawing a bag with good potatoes is greater than 0

The probability of drawing a bag with bad potatoes as a decimal .

The probability is 20% which means 20 by hundred , which means there is a chance of being its ok.

probability of bad potatoes = 2/20

=1/10

=0.1

probability of good potatoes = 1- ( probability of bad potatoes)

=1-0.1

=0.9

To learn more about probability

brainly.com/question/173579

#SPJ4

3 0

1 year ago

Best Buy is displaying 15 laptops for a big store sale. The laptops include 6 identical Dells, 4 identical Chromebooks, and 5

Alchen [17]

Answer:

630,630 different arrangements are possible for the given laptops.

Step-by-step explanation:

Total number of laptops = n = 15

Number of identical Dell laptops = 6

Number of identical Chromebooks = 4

Number of identical Mackbooks = 5

We have to find in how many ways can the laptops be arranged. Number of arrangement of objects is calculated using Permutations as the order of objects matter during the arrangement. The formula to calculate the number of possible arrangements when there are similar objects is given as:

$\frac{n!}{a!b!c!...}$

Here n is the total number of objects and a,b, and c represent the number of identical objects. Using the given values we get:

$\frac{15!}{6!4!5!} = 630630$

This means 630,630 different arrangements are possible for the given laptops.

4 0

2 years ago