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Ganezh [65]
3 years ago
6

A right triangle has one leg with a length of 48 and a hypotenuse with a length of 80. What is the length of the other leg?

Mathematics
1 answer:
victus00 [196]3 years ago
4 0
Using the pythagorean theorem (a^2 + b^2 = c^2), this would make the equation 48^2 + b^2 = 80^2 (the hypotenuse must be plugged in as the "c" value).

Once you solve, this becomes 2304 + b^2 = 6400.

Subtract 2304 from 6400 and you get b^2 = 4096.

Take the square root of 4096 and you get b=64.


The answer is 64.
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1.5 x 2= 3 = 20%
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8 0
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Finals are​ over, and you are moving back home for the summer. You need to rent a truck to move your possessions from the colleg
rewona [7]
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5 0
3 years ago
Use the properties of exponents to determine the value of aa for the equation:
Phantasy [73]

Answer:  a = -2/3

Step-by-step explanation:

Let's start by multiplying both sides by x to simplify:

$4^{1/3} = x^a \times x$

$4^{1/3} = \underbrace{x \times x \times x \times \cdots \times x}_{a\ \textrm{times}} \times \,x$

$4^{1/3} = \underbrace{x \times x \times x \times \cdots \times x \times x}_{a+1\ \textrm{times}}$

4^{1/3} = x^{a+1}

Looking only at the exponents, it seems like 1/3 = a+1, so a = \boxed{-2/3}.

5 0
2 years ago
If n+h/5=f+9/9, then n/5=
Ann [662]
------------------------------------------------------------------
Question
------------------------------------------------------------------
\boxed { \frac{n+h}{5}  =  \frac{f+9}{9}}

------------------------------------------------------------------
Split the fraction on the left
------------------------------------------------------------------
\boxed { \frac{n}{5} + \frac{h}{5}  = \frac{f + 9}{9}}

------------------------------------------------------------------
Take away h/5 from both sides
------------------------------------------------------------------
\boxed { \frac{n}{5}  = \frac{f+9}{9} - \frac{h}{5}}

------------------------------------------------------------------
Change the denominator to be the same
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}

------------------------------------------------------------------
Put it into single fraction
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }


\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}

6 0
3 years ago
Hep asappppppppppppp
schepotkina [342]

Answer:

(6 , -1)

Step-by-step explanation:

2x+  y  = 11   ----------------(I)

y = 11 - 2x --------------------(II)

\frac{1}{2}x - 5y = 8

Multiply the whole equation by 2

2*\frac{1}{2}x -2*5y = 2*8

x - 10y = 16 --------------------(III)

Substitute y = 11- 2x in equation (III)

x - 10(11 - 2x) = 16

x - 110 + 20x = 16

21x - 110 = 16

21x = 16 +110

21x = 126

x = 126/21

x = 6

Plugin x = 6 in equation (II)

y = 11 - 2*6

y = 11 - 12

y = -1

5 0
2 years ago
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