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Brrunno [24]
3 years ago
9

there were 18 cans ona shelf. a customer bought 7 cans. then jake put 6 cans on the shelf. how many cans are on the shelf now?

Mathematics
2 answers:
Rainbow [258]3 years ago
3 0
18-7+6=17

17 cans are on the shelf.
Elis [28]3 years ago
3 0
18-7 =11
11+6 =17

So 17 is your answer :)
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The equations x minus 2 y = 4, 4 x + 5 y = 8, 6 x minus 5 y = 15, and x + 2 y = 0 are shown on the graph below.
marin [14]

Answer:

Step-by-step explanation:

.1x7 8, 6

5 0
3 years ago
Read 2 more answers
Carmen cut a 12 meter piece of cloth into three pieces. The first two pieces were each
astraxan [27]

Answer:

6 Meters long

Step-by-step explanation:

3+3=6

12-6=6

8 0
3 years ago
Use an equation to write 2 x (2/3) as a multiple of a unit fraction.
motikmotik

Simplify the expression.
Exact Form
4/3
Decimal Form:
1.3
Mixed Number Form:
1 1/3
5 0
2 years ago
6. The heights of men selected from a particular population have a normal distribution with mean 68 inches and standard deviatio
olchik [2.2K]

Answer:

a) the proportion is 0.159 (15.9%)

b) the proportion is 0.524 (52.4%)

c) Ralph is 70.958 inches tall

Step-by-step explanation:

defining our random variable X= heights of men , then we can define the standard random variable Z as

Z= (X- μ)/σ , where  μ is the population's mean and σ is the corresponding standard deviation of X

then for X=72

Z= (X- μ)/σ

Z= (72-68)/4 = 1

a) P(X> 72) = P(Z> 1) = 1-0.841 = 0.159 (using standard normal distribution tables)

b) for X=64 and X=74

Z₁= (64 -68)/4 = -1

Z₂= (74-68)/4 = 1.5

then

P(68<X< 74) = P(-1<Z <1.5) 0 = P(Z<1.5) - P(Z<-1) =  0.933- 0.159 =0.774

c) Z₃ = 0.933 - 0.774*0.25 = 0.7395

thus

Z₃= (X₃- μ)/σ →X₃ =μ+ Z₃*σ = 68 + 0.7395*4  = 70.958 inches

therefore Ralph is 70.958 inches tall

4 0
3 years ago
Rewrite the polynomial-9x^5+36x^4+189x^3 in factored form, using the factoring method method you prefer.
ozzi

The polynomial 9x^5+36x^4+189x^3 in factored form is -9 x \times x \times x \times(x-7) \times(x+3)

<u>Solution:</u>

Given, polynomial equation is -9 x^{5}+36 x^{4}+189 x^{3}

We have to find the factored form of the above given polynomial equation.

Let us solve it by grouping.

Now, take the polynomial ⇒ -9 x^{5}+36 x^{4}+189 x^{3}

By taking common term out, we get

\rightarrow-9 x^{3}\left(x^{2}-4 x-21\right)

\rightarrow-9 x^{3}\left(x^{2}-(7-3) x-7 \times 3\right)

Grouping the terms we get,

\rightarrow-9 x^{3}\left(\left(x^{2}-7 x\right)+(3 x-7 x^3)\right)

Taking common terms out from each group,

\rightarrow-9 x^{3}(x(x-7)+3(x-7))

\Rightarrow-9 x^{3}((x-7)(x+3))

\rightarrow-9 x \times x \times x \times(x-7) \times(x+3)

Thus the factored form of polynomial is found out

4 0
3 years ago
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