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Leno4ka [110]
3 years ago
8

A 2-card hand is drawn from a standard deck of 52 cards. find the probability that the hand contains the given cards. two of the

same suit
Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0
This probability is the same as 1-(two different suited cards). Your first card can be any of the 52 cards. Your second card must be any of the 39 different suited remaining 51 cards. So the answer is 1 - (52/52)(39-51). Note: I assumed there was no replacement.
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z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

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Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

\hat p=0.64 estimated proportion of interest

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true proportion is higher than 0.5:  

Null hypothesis:p =0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

p_v =P(z>2.43)=0.0075 \approx 0.008  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

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3 years ago
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