The product of n and 5

One fifth of a number plus one third of a different number

skad [1K]

1/5x+ 1/3y would be the correct response.

3 0

3 years ago

How many 1/9's in 31

Setler79 [48]

Answer is 279

Step-by-step explanation:

Lets do the following:
How many 1/9 are there in 1? Easy! 9. We can corroborate this by summing 1/9 nine times of multiplying 1/9 nine times. In both cases the result is 9.
Then, how many 1 are there in 31? Easier!! 31. Is we sum the number 1 thirty one times, the result is 31.
Now let join both results:
If each 1 has nine 1/9, and there are thirty one 1s in 31, then in 31 we have 31*9=279 1/9s. This is:
31*1 = 31 * 9 (1/9) = 279 * (1/9)

8 0

3 years ago

What’s the mean,median, and mode of 11,14,16,15,32,23,27,27,23,43 ?

alexdok [17]

Step-by-step explanation:

mean- add all number/by the total nos

=231/10=23.1

median - the middle value of data after arranging in ascending order

11,14,15,16,23,23,27,27,32,43

therefore the median is 23

mode - is the no that has occurred more

so mode will be 23 and 27

8 0

4 years ago

Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of education the students r

galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1095, \pi = \frac{478}{1095} = 0.4365$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612$

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

5 0

3 years ago

The volume of a cylinder is given by the formula y = rrah, where r is the radius of the cylinder and h is the height.

nekit [7.7K]

The third one is the correct answer I think

7 0

3 years ago