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4 years ago

Y = 7ex, y = 7e−x, x = 1; about the y-axis

1 answer:

3 0

A "typical" cylindrical shell of wall thickness dx at x=x will have the length (in the y-direction) L = (e^x – e^-x).

Rotating this shell about the y-axis generates a volume dV = 2.π.x.L = 2.π.x.(e^x – e^-x).dx 

Total volume V of all such cylindrical shells in the given range = 2.π.∫x.(e^x – e^-x).dx 

= 4.π.[x.cosh(x) – sinh(x)] from 0 to 1. Now insert the limits and we obtain: 

= 4.π.[1.543 – 1.175] = 4.624 cubic units

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Loe's walkie-talkie is at 20% when fully charged the battery lasts 12 hours Leo thinks the walkie-talkie will last his entire 3

katen-ka-za [31]

False because it will only last 2.4 hours. 12 x 20% = 2.4. Hope I could help! :)

5 0

3 years ago

He has a record contract that Pays him a base rate of $200 a month and then additional $12 for each album that he sells. Last mo

slavikrds [6]

Answer:

He sold a total of 37 albums last month.

Step-by-step explanation:

Given,

Total earned money = $644

Base payment = $200

Additional payment for each album = $12

We have to find the number of albums sold by him.

Solution,

Let the number of albums be 'a'.

Total earned money is the sum of base payment and additional payment for each album multiplied with number of albums sold.

So framing in equation form, we get;

$644=200+12a$

Subtracting both side by '200' using subtraction property, we get;

$200+12a-200=644-200\\\\12a=444$

Now dividing both side by '12' using division property, we get;

$\frac{12a}{12}=\frac{444}{12}\\\\a=37$

Hence he sold a total of 37 albums last month.

3 0

4 years ago

256 divided by 11 equals what

fgiga [73]

23.27

Use a calculator

8 0

4 years ago

Which point could be on the line that is parallel to line KL and passes through point M?

professor190 [17]

Answer:

(8,-10)

Step-by-step explanation:

step 1

Find the slope of line KL

K(-6,8),L(6,0)

m=(0-8)/(6+6)

m=-8/12=-2/3

step 2

Find the slope of the line that is parallel to KL

we know that

If two lines are parallel , then their slopes are the same

therefore

The slope of the parallel line to KL is m=-2/3

step 3

Find the equation of the line parallel to KL that pass through the point M

M(-4,-2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y+2=-(2/3)(x+4)

step 4

Verify the points

we know that

If the point lie on the line, then the point must satisfy the equation of the line

case a) (-10,0)

substitute the value of x and the value of y in the equation and then compare the result

-10+2=-(2/3)(0+4)

-8=-8/3 -----> is not true

therefore

The point is not on the line

case b) (-6,2)

substitute the value of x and the value of y in the equation and then compare the result

2+2=-(2/3)(-6+4)

4=4/3 -----> is not true

therefore

The point is not on the line

case c) (0,-6)

substitute the value of x and the value of y in the equation and then compare the result

-6+2=-(2/3)(0+4)

-4=-8/3 -----> is not true

therefore

The point is not on the line

case d) (8,-10)

substitute the value of x and the value of y in the equation and then compare the result

-10+2=-(2/3)(8+4)

-8=-8 -----> is true

therefore

The point is on the line

3 0

3 years ago

Read 2 more answers

Please help me with this

Gemiola [76]

Answer:

Step-by-step explanation:

Gabriela has solved incorrectly. 5 should distributed to 9x & (-8) and 4 should be distributed between x & 2

5(9x - 8) = 4*(x + 2)

5*9x - 5*8 = 4*x + 4*2

45x - 40 = 4x + 8

Subtract 4x from both sides

45x - 4x - 40 = 8

41x - 40 = 8

Add 40 to both sides

41x = 8 + 40

41x = 48

x = 48/41

6 0

3 years ago